Tag: units and measurement: error analysis

Questions Related to units and measurement: error analysis

A packet contains silver powder of mass $20.23g\pm 0l01g$. Some of the powder of mass $5.75g\pm 0.01g$ is taken out from it. The mass of the powder left back is

  1. $14.48g\pm 0.00g$

  2. $14.48g\pm 0.02g$

  3. $14.5g\pm 0.1g$

  4. $14.5g\pm 0.2g$


Correct Option: B

All the numbers that can be formed using the digits, are arranged in the increasing order of magnitude. The rank of the number is (repetition not allowed).

  1. $58$

  2. $15$

  3. $50$

  4. $16$


Correct Option: A

The number of significant figures in 3400 is :

  1. 4

  2. 1

  3. 3

  4. 2


Correct Option: D
Explanation:

Trailing zeros in a whole number are not significant.Hence $3400$ has 2 significant digits only.

Therefore, option D is correct.

The distance $s$ traveled by a particle in time $t$ is
$s=ut-\cfrac{1}{2}g{t}^{2}$
The initial velocity of the particle was measured to be $u=1.11\pm 0.01m/s$ and the time interval of the experiment was $t=1.01\pm 0.1s$. The acceleration was taken to be $g=9.8\pm 0.1m/{s}^{2}$. With these measurements, the student estimates the total distance traveled. How should the student report the result?

  1. $1.121\pm 0.m$

  2. $1.1\pm 0.1m$

  3. $1.12\pm 0.07m$

  4. $1.1\pm 0.07m$


Correct Option: C

The diameter and height of a cylinder are measured by a meter scale to be $12.6\pm 0.1$ cm and $34.2\pm 0.1$ cm ,respectively. What will be the value of its volume in appropriate significant figures?

  1. $4264\pm 81{ cm }^{ 3 }$

  2. $4260\pm 80{ cm }^{ 3 }$

  3. $4264.4\pm 81.0{ cm }^{ 3 }$

  4. $4300\pm 80{ cm }^{ 3 }$


Correct Option: C

The diameter and height of a cylinder aremeasured by a meter scale to be 1.6$\pm 0.1$$\mathrm { cm }$ and 5.0$\pm 0.1 \mathrm { cm }$ , respectively. What will be the value of its volume inappropriate significant figures? 

  1. 4300$\pm 80 \mathrm { cm } ^ { 3 }$

  2. 4260$\pm 80 \mathrm { cm } ^ { 3 }$

  3. 4264$\pm 81 \mathrm { cm } ^ { 3 }$

  4. 10.0$\pm .325 \mathrm { cm } ^ { 3 }$


Correct Option: D

In the final answer of the expression  $\dfrac { ( 29.2 - 20.2 ) \left( 1.79 \times 10 ^ { 5 } \right) } { 1.37 }.$  The number of significant figures is

  1. $1$

  2. $2$

  3. $3$

  4. $4$


Correct Option: C

The number of significant figures reduced in

  1. Addition

  2. Substraction

  3. Multiplication

  4. division


Correct Option: C