Tag: some useful compounds in everyday life

Questions Related to some useful compounds in everyday life

Which one of the following processes does not occur during formation of $CH{ Cl } _{ 3 }$ from ${ C H } _{ 3 }OH$ and bleaching powder ?

  1. Hydrolysis

  2. Oxidation

  3. Reduction

  4. Chlorination


Correct Option: C
Explanation:
The process that does not occur during the formation of $CHCl _3$ from $CH _3OH$ and Bleaching Powder is REDUCTION PROCESS.
In $CHCl _3$ oxidation state of carbon is +2 and in methanol oxidation state of carbon is-2. This is reduction.

Which of the following negative radical is present in bleaching powder?

  1. Hypochlorite

  2. Chlorate

  3. Chloride

  4. Both $(A)$ and $(C)$


Correct Option: D
Explanation:
Bleaching powder is calcium oxychloride given by the formula $CaOCl _2$ 

Hence, negative radicals are $OCl^-$ & $Cl^-$ i.e. hypochlorite & chloride.

Action bleaching poweder on ethyyl alcohol gives?

  1. Chloroform

  2. Dichloro methane

  3. Trichloro ethane

  4. Ethylene chloride


Correct Option: A
Explanation:

The reactions involved are-

$CaOCl _2 + H _2O \rightarrow Ca(OH) _2 + Cl _2$

$C _2H _5OH + [O] \rightarrow CH _3CHO$

$CH _3CHO + Cl _2 \rightarrow CCl _3HO$

$CCl _3CHO + Ca(OH) _2 \rightarrow CHCl _3 + (HCOO) _2Ca$


Hence the product formed is having Chloroform and the correct option is A.

Bleaching properties of bleaching powder are due it its:

  1. Oxidizing properties

  2. Reducing properties

  3. Basic properties

  4. Disinfecting properties


Correct Option: A
Explanation:

Chlorine bleaches by the process of oxidation. It needs moisture for its bleaching action.

Chlorine reacts with water to form hydrochloric and hypochlorous acids.

$Cl _2 + H _2O \rightarrow HCl + HClO$

Hypochlorous acid is unstable, and it easily dissociates to form nascent oxygen.

$HClO \rightarrow HCl + [O]$

Nascent oxygen is a more powerful oxidising agent. Its formation is responsible for the bleaching nature of chlorine in the presence of moisture.

Hence option A is correct answer.

Oxidation number of $Cl$ in ${ CaOCl } _{ 2 }$ (bleaching powder) is:

  1. zero, since it contains ${ Cl } _{ 2 }$

  2. $-1$, since it contains ${ Cl }^{ - }$

  3. $-1$, since it contains ${ ClO }^{ - }$

  4. $+1$ and $-1$ since it contains ${ ClO }^{ - }$ and ${ Cl }^{ - }$


Correct Option: D
Explanation:
In bleaching powder,$CaOCl _2,$ the two $Cl$ atoms are in different oxidation states i.e.,one $Cl$ atom having oxidation number of $-1$ and the other as $OCl^-$ having oxidation number of $+1$.
Therefore,$+1$ and $-1$ Since it contains $ClO^-$ and $Cl^-$
Ans is option $D$

Bleaching powder is obtained by treating chlorine with ________ .

  1. $CaO$

  2. $CaC{O _3}$

  3. $CaS{O _4}$

  4. $Ca{(OH) _2}$


Correct Option: D

Bleaching powder is disinfectant for purification of water when water born germs are killed. But disinfectant activity is destroyed. It is due to its disproportionation into:

  1. $ CaCl _2$  and $Cl _2 $

  2. $ CaCl _2$  and $Ca(ClO _3) _2 $

  3. $ CaO$  and $Cl _2 $

  4. $ CaO, Cl _2$ and $CaCl _2 $


Correct Option: B
Explanation:
Bleaching powder is disinfectant for purification of water when water born germs are killed. But disinfectant activity is destroyed because of the degradation of high grade of bleaching powder.
These include disproportionation to give $Ca(ClO _3) _2$ and $CaCl _2$, and with the evolution of $Cl _2$ or $O _2$ depending on the presence or absence of water.

Option B is the correct answer.

The active constituent of bleaching powder is:

  1. $ Ca(OCl) _2$

  2. $ Ca(OCl)Cl $

  3. $ Ca(ClO _2) _2 $

  4. $ Ca(ClO _2)Cl$


Correct Option: A
Explanation:

The active constituent of bleaching powder is: $Ca(OCl) _2$

$ CH _3CH _2OH$ on reaction with bleaching powder forms:

  1. $ CHCl _3 $

  2. $ CClCHO$

  3. $ CH _2ClCHO$

  4. $ CCl _4 $


Correct Option: A
Explanation:
When bleaching powder is distilled with alcohol, chloroform is produced.

$CH _3CH _2OH +CaOCl _2 \rightarrow CHCl _3 +Ca(HCOO) _2$

Hence, option A is correct.

Slaked lime and chlorine reacts to produce :

  1. quick lime

  2. $CaCl _2$

  3. $CaOCl _2$

  4. mixture of $CaCl _2$ and $Ca(OCl _2)$


Correct Option: D
Explanation:

$Ca(OH) _2+\underset{\text{dry}}{Cl _2}\xrightarrow{below\,35^oC} \underset{\text{Bleaching powder}}{CaOCl _2 + H _2O}$


$2Ca(OH) _2 + 2Cl _2\xrightarrow{red\, heat} 2CaCl _2 + 2H _2O + O _2\uparrow$