Tag: masses of atoms and molecules

Questions Related to masses of atoms and molecules

What is the atomic mass of sodium?

  1. $22\ g/mol$

  2. $23\ g/mol$

  3. $11\ g/mol$

  4. $20\ g/mol$


Correct Option: B
Explanation:

A relative atomic mass is a measure of how heavy atoms are. It is the ratio of the average mass per atom of an element from a given sample to 1/12 the mass of a carbon-12 atom.

The relative atomic mass in 1 mole of isotopes of sodium atoms is 23 g/mol.

What is the relative atomic mass of cadmium?

  1. 112.411 amu

  2. 20.00 amu

  3. 21.00 amu

  4. 20.43 amu


Correct Option: A
Explanation:

The relative atomic mass is an average of the atomic masses of all the different isotopes in a sample, with each isotope's contribution to the average determined by how big a fraction of the sample it makes up.
The relative atomic mass of Cadmium is 112.411 amu.

Which of the following is/are correct?

  1. One atomic mass unit is a mass unit equal to exactly one -twelfth (1/12th) the mass of one atom of carbon-12.

  2. One atomic mass unit is a mass unit equal to exactly one - sixteenth (1/16th) the mass of one atom of oxygen-16.

  3. The relative atomic mass of the atom of an element is defined as the average mass of the atom, as compared to 1/12h the mass of one carbon-12 atom.

  4. None of the above.


Correct Option: A,B,C
Explanation:

The following are correct. One atomic mass unit is a mass unit equal to exactly one -twelfth (1/12th) the mass of one atom of carbon-12.
One atomic mass unit is a mass unit equal to exactly one - sixteenth (1/16th) the mass of one atom of oxygen-16.
The relative atomic mass of the atom of an element is defined as the average mass of the atom, as compared to 1/12h the mass of one carbon-12 atom.
For example, the mass of one carbon-12 atom is 12 amu. The mass of one magnesium-24 atom is 24 amu. The mass of one calcium-40 atom is 140 amu.

Oxygen occurs in nature as a mixture of isotopes $^16O$, $^17O$ and $^18O$ having atomic masses of 15.995 u, 16.999 u and 17.999 u and relative abundance of 99.763%, 0.037%, and 0.200% respectively. What is the average atomic mass of oxygen?

  1. 15.999 u

  2. 16.999 u

  3. 17.999 u

  4. 18.999 u


Correct Option: A
Explanation:
 Average atomic mass of an element existing in different isotopes is given by:
$M _{ avg }=\dfrac { \sum _{ i=1 }^{ n }{ { M } _{ i }{ A } _{ i } }  }{ \sum _{ i=1 }^{ n }{ A _{ i } }  } $
where $M _i=$atomic mass of an isotope with relative abundance of $A _i$
Given:$M _1=15.995 u,A _1=99.763,M _2=16.999 u, A _2=0.037,M _3= 17.999 u, A _3=0.200$
on subtitutiing we get:
${ M } _{ avg }=\dfrac { 15.995\times 99.763+16.999\times 0.037+17.999\times 0.200 }{ 99.763+0.037+0.200 } $
${ M } _{ avg }=15.999\ u$
option A is correct

For every ,one $^{37}Cl$ isotope there are three $^{35}Cl$ isotopes, in a sample of chlorine. What will be the average atomic mass of chlorine?

  1. 35

  2. 37

  3. 35.5

  4. 35.6


Correct Option: C
Explanation:
Average atomic mass of an element existing in different isotopes is given by:
$M _{ avg }=\dfrac { \sum _{ i=1 }^{ n }{ { M } _{ i }{ A } _{ i } }  }{ \sum _{ i=1 }^{ n }{ A _{ i } }  } $
where $M _i=$atomic mass of an isotope with relative abundance of $A _i$
Given:$M _1=37 u,A _1=1,M _2=35 u, A _2=3$
on subtitutiing we get:
${ M } _{ avg }=\dfrac { 37\times 1+35\times 3 }{ 1+3 } $
${ M } _{ avg }=35.5\ u$
option C is correct

One gm metal $M^{3+}$ was discharged by the passage of $1.81\times 10^{23}$ electrons. What is the atomic mass of metal?

  1. $8g/mol$

  2. $9g/mol$

  3. $10g/mol$

  4. None of these


Correct Option: C
Explanation:
Applying faraday's first law-
$ \dfrac{Q}{F} = \dfrac{Wt}{Mwt}\times V.f.$
$ \dfrac{ne}{F}= \dfrac{1}{Mwt}\times 3$
$  Mwt         = \dfrac{1\times F\times 3}{ne}$
$  Mwt         = 10\dfrac{gm}{mol}$

The relative atomic mass of $ Ne$ is $20.$ Its relative molecular mass is:

  1. $10$

  2. $20$

  3. $30$

  4. $40$


Correct Option: B
Explanation:

The relative atomic mass of  $Ne$ is $20.$ Its relative molecular mass is also $20$ as Neon is mono-atomic.

1 ml ${ O } _{ 2 }$ will be equal to :

  1. $4g$ equivivalent oxygen

  2. $2g$ equivivalent oxygen

  3. $32g$ equivivalent oxygen

  4. $8g$ equivivalent oxygen


Correct Option: A
Explanation:

Weight of $1$ mole of $O _2=32g$

$1g$ equivalent is the weight of substance which displaces $8g$ of $O _2$
$\therefore 32g$ of $O _2=\cfrac {32}{8}=4g$ equivalents of oxygen .

How many grams of carbon dioxide is dissolved in 1 litre bottle of carbonated water if the manufacturer uses a pressure of 2.4 atmosphere in the bottling process at 25 degree Celsius?

  1. 1.52

  2. 4.2

  3. 3.1

  4. 3.52


Correct Option: D

Common salt obtained from sea-water contains $ 8.775\%$ $NaCl$ by mass. The number of formula units of $NaCl$ present in 25 g of this salt is :

  1. $3.367 \times { 10 }^{ 23 }$ formula units

  2. $2.258 \times { 10 }^{ 22 }$ formula units

  3. $3.176 \times {10 }^{ 23 }$ formula units

  4. $4.73 \times {10 }^{ 25}$ formula units


Correct Option: A