Tag: use of commas and comparison and number systems

Questions Related to use of commas and comparison and number systems

The value of $200$ mm added to $800$ m is

  1. $801 m$

  2. $800.200m$

  3. $802m$

  4. $800m$


Correct Option: B
Explanation:

800m, 200mm

$100mm = 0.1 m$


$1mm=$$\dfrac{0.1}{{100}}m$

$200mm=$$\dfrac{0.200}{{100}}m$

$=2m$

So, $800.200m$

Thirty one crore fifty-five lakh thirty-two thousand eight hundred in numerals is written as

  1. $31,55,32,800$

  2. $3,01,55,32,800$

  3. $3,15,05,32,800$

  4. $3,15,53,02,800$


Correct Option: A
Explanation:

In Indian System, the numeral is Thirty one crore, fifty-five lakh thirty-two thousand eight hundred can be written as $31,55,32,800$.

1 billion = __________ crores.

  1. 1

  2. 10

  3. 100

  4. 1000


Correct Option: C
Explanation:

correct option is C..

__________ is equivalent to ten lakh in International System of numeration.

  1. Hundred thousand

  2. Ten million

  3. One million

  4. Ten thousand


Correct Option: C
Explanation:

$1$ million is equal to $10$ lakhs.


Hence the correct answer is option C.

Kiran had $85$ currency notes in all, some of which were of Rs. $100$ denomination and the remaining of Rs. $50$ denomination. The total amount of all these currency notes was Rs. $5000$. How much amount did she have in the denomination of Rs. $50$?

  1. Rs. $2725$

  2. Rs. $3500$

  3. Rs. $1500$

  4. Rs. $2800$


Correct Option: B
Explanation:

Let $100$ Rs note be $x$ and $50$ Rs note be $y$

Total number of notes =$x+y=85$................(1)
Total amount of these currency notes + $5000=100x+50y$.............(2)
Multiplying equation 1 with $50$
therefore we get $50x+50y=4250$.......(3)
Subtracting equation 3 from equation 2, we get
$50x=750$
$x=15$
Substituting $x=15$ in equation 1, weget $y=70$
Amount in dominnation of $50$ Rs=$70\times 50=3500$