Tag: in the world of stars

Questions Related to in the world of stars

Astronomers use light years to measure the speed of light.

  1. True

  2. False


Correct Option: B
Explanation:

Heavenly bodies are very far away from each other. It is impossible to measure their distances by using conventional units like miles and kilometres. Hence light year is used to measure the distance of heavenly bodies from each other.

All the stars are at the same distance from us. This statement is

  1. True

  2. False


Correct Option: B
Explanation:

Our Sun is the nearest star to the Earth. After the Sun, the next nearest star is 4.3 light years away. A light year is the distance light travels in one year. One light year is 10 trillion kilometers. Hence, all the stars are not the same distance from our Earth. They are at different distances. Hence, given statement is false.

The $6563 \mathring {A}$ line emitted by hydrogen atom in a star is found to be red shifted by $5\mathring{A}$. the speed with which the star is receding from the earth is:

  1. $17.3\times 10^3 $ m/s

  2. $4.29 \times 10^7 $m/s

  3. $3.39 \times 10^5 $m/s

  4. $ 2.29 \times 10^5$ m/s


Correct Option: D
Explanation:

$\dfrac{\triangle v}{v}=\dfrac{V _{radiant}}{C}$
$v=\dfrac{C}{\lambda}$
$d.v=\dfrac{C}{\lambda^2}.dv=\dfrac{\dfrac{x}{\lambda^2}}{\dfrac{C}{\lambda}}=\dfrac{d\lambda}{\lambda}$
$\dfrac{d\lambda}{\lambda }=\dfrac{V _{radial }}{C}$
$\dfrac{5 \times 10^{-10}}{6563 \times 10^{-10}}=\dfrac{C _{radial}}{3\times 10^8}$
Calculate $V _radial=\dfrac{5}{6563}\times 3\times 10^8$
$=\dfrac{15}{6563}\times 10^8$
$\dfrac{15}{6.56}\times 10^5$
$2.29\times 10^5m/s$

A star is seen to be rising on the eastern horizon at $23:00$ hrs. At what time the star will rise 2 days later

  1. $00:00$ hrs

  2. $21:40$ hrs

  3. $23:20$ hrs

  4. $23:00$ hrs


Correct Option: D
Explanation:
The stores appear to be static when seen from earth thus they only appear to be moving due to earth's rotation about its axis. It takes exactly $24$ hors to complete one rotation. So after days $(2\times 24\ hrs)$, the far will be seen rising at the same time
$(i.e., 23:00\ hrs)$

Which of the following is different from others?

  1. light year

  2. parsec

  3. astronomical unit

  4. micron


Correct Option: D

One light year is equal to

  1. 3.26 parsec

  2. 3.26km

  3. 3.26 A.U.

  4. $\displaystyle \frac{1}{3.26}$ parsec


Correct Option: D
Explanation:

One light year is the distance travelled by the light in one year. So,

$1$Parse $=3.08\times { 10 }^{ 16 }$m
$1$ light year$9.46\times { 10 }^{ 15 }$m
So
$1$ light year $=9.46\times { 10 }^{ 15 }$ parsec
                       $=3.08\times { 10 }^{ 16 }$
$1$ light year $=0.306$ parsec
                     $=\cfrac { 1 }{ 3.26 } $ parsec

Which of the following is the largest astronomical unit?

  1. light year

  2. parsec

  3. KM

  4. astronomical unit


Correct Option: B

We live on the outer edge of a spiral type of galaxy called the milky way, which is about ........light years in diameter

  1. $10^5$

  2. $10^4$

  3. $10^3$

  4. 10


Correct Option: A
Explanation:

The diameter of milky way is about ${ 10 }^{ 5 }$ light years


Which of the following is the smallest unit of distance?

  1. light year

  2. parsec

  3. astronomical unit

  4. km


Correct Option: D
Explanation:

Out of these four units kilometer is the smallest unit.

The nearest star to the Earth (apart from the Sun) is 'alpha centauri' which is about .......... away form the Earth

  1. 4.3 light years

  2. 3.26 light years

  3. $4.3 \times 10^{12}$ km

  4. $3.26 \times 10^{15}$ km


Correct Option: A
Explanation:

Alpha century is a star system closest to earth other than sun. Its distance from the earth is about $4.367$ light years.