If the length of filament of a heater is reduced by 10%, the power of the heater will
increase by about 9%
increase by about 11%
increase by about 19%
increase by about 10%
$P=\dfrac { { V }^{ 2 } }{ R } \ R=\dfrac { \rho l }{ A } \ \therefore P=\dfrac { { V }^{ 2 }A }{ \rho l } $