In Redox reaction oxidation state changes
(a) In $ SO _{4}^{-2}, $ Its $ S^{+6} $
In $ SO _{3}, $ Its $ S^{+6}$
$ \therefore$ In $SO _{4}^{-2}\rightarrow SO _{3},$ there is no change
in oxidation state of $ O^{+5}$
$ \therefore $ Non- redox reaction
(b) In $ Cr _{2}O _{7}^{-2} $
Lets oxidation state of Cr be x
$ \therefore 2(x)+7(-2) = -2 $
$ \therefore 2x+(-14) = -2 $
$ \therefore 2x = 12 $
$ \therefore x = 16 $
In $ CrO _{4}^{-2} $
Let oxidation Sate of Cr be y
$ y+4(-2) = -2 $
$ y-8 = -2 $
$ y = +6 $
$ \therefore $ oxidation of Cr remain same
$ \therefore $ Non- redox Readtion
(C) In $ PO _{4}^{-3}, $ Its $ P^{+} $
and In $ P _{2}O _{7}^{-4} $
Let oxidation sate of P be x
$ 2x+7(-2) = -4 $
$ 2x-14 = -4 $
$ \therefore 2x = 10 $ $ \therefore $ Non - redox Reaction
$ \therefore x = 5 $
(d) In $ C _{2}O _{4}^{-2},$ Its $ C^{+3}$
In $ Co _{2},$ Its $ C^{+4} $ $ \therefore $ Redox reaction
Hence, the correct options are $\text{A}$, $\text{B}$ and $\text {C}$