Tag: properties of substances

Questions Related to properties of substances

Pick up the correct statement:

chemistry substances in the surroundings - their states and properties elastic behaviour of solids elastic and plastic substances properties of substances

  1. Cubic crystals exhibit isotropic nature with respect to therma expansion

  2. Anisotropic solids expand in one direction and contract in perpendicular direction

  3. Many of the crystals are anisotropic solids

  4. Rock salt crystal exhibits isotropic nature with respect to thermal expansion

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Correct Option: C

The nearest approach to a perfect plastic body is

physics properties of material substances elastic behaviour of solids elastic and plastic substances properties of substances

  1. diamond

  2. quartz fiber

  3. putty

  4. none of these

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Correct Option: B

The materials, which do not show a fixed trend of deformation vs. applied force, are called:

physics properties of material substances elastic behaviour of solids elastic and plastic substances properties of substances

  1. inelastic materials

  2. plastic materials

  3. elastic materials

  4. rigid materials

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Correct Option: A
Explanation:

Elastic materials are those that follow the Hooke's law, which is that the deformation produced in a material is directly proportional to the stress applied to it, and the material is recoverable after the deformation force is removed.

Inelastic materials are those that do not follow this relationship. They do not show a fixed trend of deformation vs applied force; in fact, they might not deform at all (rigid materials) or the deformation observed is not completely recoverable.

The density of a cuboid of mass 200 g with dimensions 2 cm $\times$ 4 cm $\times$ 5 cm is

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. 1000 kg m$^{-3}$

  2. 3000 kg m$^{-3}$

  3. 5000 kg m$^{-3}$

  4. 2000 kg m$^{-3}$

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Correct Option: C
Explanation:
The density of a body is defined as the amount of substance contained per unit volume.
Density $=\dfrac{mass}{volume}$

$\displaystyle d = \frac{0.2 kg}{40  cm^3} = \frac{0.2 \times 10^6}{40} kg  m^{-3}$

$=5000  kg  m^{-3}$

A wire of length 50 cm has a mass of 20 gm. It its radius is halved by stretching, its new mass per unit length will be

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. 0.4 g cm$^{-1}$

  2. 0.2 kg m$^{-1}$

  3. 0.1 g cm$^{-1}$

  4. 0.2 g cm$^{-1}$

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Correct Option: C
Explanation:

On stretching, volume remains constant. Hence on decreasing the radius by half, the length of the wire becomes quadrupled. 
Mass per unit length $\displaystyle = \frac{20}{4 \times 50 cm}$
$=0.1  g  cm^{-1}$

Density of water is :

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. 1 g cm$^{-3}$

  2. 100 kg m$^{-3}$

  3. 1000 kg m$^{-3}$

  4. None

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Correct Option: A,C
Explanation:

 Density of water = 1 g $ cm^{-3 }$ = 1000 kg $ m^{-3}$

so option (A) and option (C) are correct

If 5 litres of kerosene has a mass of 5 kg, then what is the density of kerosene?

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. 500 kg/$m^3$

  2. 1000 kg/$m^3$

  3. 100 kg/$m^3$

  4. 50 kg/$m^3$

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Correct Option: B
Explanation:

Density of kerosene $= \displaystyle \frac{mass}{volume}$
$\displaystyle = \frac{5  kg}{5  litres}= \frac{5kg}{5 \times 10^{-3}m^3} = 1000 kg  m^{-3}$

Two spheres are having the ratio of their densities 1:3 and masses in 3:4 respectively. Find the ratio of their volumes. i.e $\dfrac{V _1}{V _2}$

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. 1:3

  2. 3:1

  3. 4:9

  4. 9:4

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Correct Option: D
Explanation:

$\displaystyle \frac{d _1}{d _2} = \frac{1}{3} ; \frac{m _1}{m _2} = \frac{3}{4}$
$d = m/v$
$\therefore \displaystyle \frac{V _1}{V _2}  = \frac{m _1}{m _2} \times \frac{d _2}{d _1} = \frac{3}{4} \times \frac{3}{1} = 9:4$

Density of air at room temperature is

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. $120 \ {g\ cm}^{-3}$

  2. $120 \ {g\ mm}^{-3}$

  3. $12 \ {g\ m}^{-3}$

  4. $1.3 \ {kg\ m}^{-3}$

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Correct Option: D
Explanation:

The density of air at NTP is $1.293 kg m^{-3}$.

So after rounding, it is $1.3 kg m^{-3}$.

If the mass of a body is 12.1 g and its density is 2.2 g/cc, its volume is.

chemistry substances in the surroundings - their states and properties measurement of density properties of substances fundamental and derived units

  1. $5.5 cm^3$

  2. $8$ cc

  3. $11$ cc

  4. $55$ cc

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Correct Option: A
Explanation:

Given:

mass $(m)=12.1g$
density $(d)=2.2g/cc$
Let the volume be $v$
As $density=\dfrac{mass}{volume}$
$d=\dfrac{m}{v}$
$v=\dfrac{m}{d}$
$v=\dfrac{12.1}{2.2}=5.5cc$