Tag: p- block elements-ii

Questions Related to p- block elements-ii

Which of the following chalcogen does not make bonds with germanium?

  1. Sulfur

  2. Selenium

  3. Tellurium

  4. Polonium


Correct Option: D
Explanation:

Chalcogens are chemical elements in group 16 of the periodic table. Germanium bonds to all natural single chalcogens except polonium.

Which of the following element has metallic lustre?

  1. $F$

  2. $Cl$

  3. $Br$

  4. $I$


Correct Option: D
Explanation:

As we move down the group the metallic character increases which impart lustrousness to the elements.

So the iodine is most lustrous.

Which of the following has most ionisation enthalpy?

  1. $F$

  2. $Cl$

  3. $Br$

  4. $I$


Correct Option: A
Explanation:

As the atomic size of the Florine is less it has more nuclear charge. So it requires more energy to remove the electron from its outer most orbit. So Florine has high ionization enthalpy and as we move down the group size increases nuclear charge decreases hence Ionization potential.

Hence option A is correect.

Which of the following is most electronegative?

  1. $F$

  2. $Cl$

  3. $Br$

  4. $I$


Correct Option: A
Explanation:

Florine is most electronegative than the other elements of that group because it has less atomic size so it attracts electrons more towards itself (Electronegativity).

Hence option A is correct.

The elements with atomic numbers 9, 17, 35, 53 and 85 belong to noble gases columnz__________.

  1. True

  2. False


Correct Option: B
Explanation:

The atomic number of elements are 9,17,35,53,85.
Electronic configuration of elements will be
9  = 2,7
17= 2,8,7
35= 2,8,18,7
53=2,8,18,18,7
85=2,8,18,18,32,7
The pattern shows that all elements have 7 electron in their outermost valence shell and all these elements belong to halogens.

Elements of which group form anions most readily:

  1. oxygen family

  2. nitrogen group

  3. halogen family

  4. carbon group


Correct Option: C
Explanation:

Halogens need to lose only one electron to form an anion, and thus, their tendency to form an anion is highest. 

In the third excited state the number of unpaired electrons in chlorine atom is:

  1. 5

  2. 7

  3. 3

  4. 1


Correct Option: B
Explanation:

The general electronic configuration of chlorine is $[Ne] 3s^{2} 3p^{5}$

When electrons are excited in chlorine, the electrons enter into 3d subshell then electronic configuration of chlorine is given as:
$[Ne] 3s^{1} 3p^{3} 3d^{3}$
Thus the number of unpaired electrons will be 7.

Which of the following shows only one oxidation state in its compounds:

  1. F

  2. Cl

  3. Br

  4. I


Correct Option: A
Explanation:

F does not have empty d-orbitals o it show only one oxidation state. In othens electrons can excite to empty d-orbitals and show variable oxidation state

The number of p-electrons in bromine atom is:

  1. 17

  2. 7

  3. 15

  4. 13


Correct Option: A
Explanation:

$Br - 35$

Its electronic configuration is given as:
$1s^22s^22p^63s^23p^64s^23d^{10}4p^5$
So, total p-electrons =6+6+5
= 17

Which one of the following is the correct order for the bond energies of halogen molecules?

  1. $Cl _2>Br _2>I _2$

  2. $Br _2>Cl _2>l _2$

  3. $l _2>Cl _2>Br _2$

  4. $I _2>Br _2>Cl _2$


Correct Option: A
Explanation:

Bond energy is inversely proportional to molecular mass as van der wall forces exist  between molecules of halogens
$\therefore$ Bond Energy order:
$Cl _2>Br _2>I _2$