Tag: the p-block elements

Questions Related to the p-block elements

When slaked lime is treated with chlorine, a compound is formed. Which of the following is correct about that compound? 

  1. It is used in bleaching cotton.

  2. It is used as disinfectant.

  3. It is a halide.

  4. It is used for sterilization of water.


Correct Option: A,B,D
Explanation:

Calcium hydroxide react with chlorine to give calcium hipochlorite, calcium chloride and water. Calcium hipochlorite which is formed in the reaction is used as bleaching agent, disinfevtant and in the sterilization process.

$2Ca(OH) _2 + 2Cl2 \rightarrow Ca(ClO) _2 + CaCl _2 + 2H _2O$.

Hence option A,B,C are correct.

The weakest $Cl-O$ bond is found in :

  1. $ClO _{4}^{-}$

  2. $ClO _{2}^{-}$

  3. $ClO^{-}$

  4. $ClO _{3}^{-}$


Correct Option: C
Explanation:

The anions given are conjugate bases of acids. According to Lowry Bronsted concept, a strong acid has weak conjugate base and a weak acid has a strong conjugate base. These anions are stabilised to greater extent, it has lesser attraction for proton and therefore, will behave as weaker base (lesser tendency for the reaction to go in backward direction). Consequently, the corresponding acid will be strongest because weak conjugate base has strong acid and strong conjgate base has weak acid and vice versa. The charge stabilization increases in the order : $ClO^- < ClO _2^- < ClO _3^- < ClO _4^-$. This means that $ClO^-$ will have minimum stability and therefore, will have maximum attraction for $H^+$. In other words $ClO^-$ will be strongest base and so its conjugate acid HClO will be the weakest acid.

Which one is most stable to heat :

  1. $HClO$

  2. $HClO _{2}$

  3. $HClO _{3}$

  4. $HClO _{4}$


Correct Option: D
Explanation:

The thermal stability of the oxyacids of halogens increases with increase in the oxidation state of halogen or with increase in the number of oxygen atoms.
 This is due to involvement of more electrons in the formation of sigma and pi bonds. The multiplicity of the Cl-O bond increases.
Thus the increasing order of the thermal stability is $HClO <HClO _2 <HClO _3<HClO _4$. Thus, $HClO _4$ is most stable to heat.

Hypervalent ion is/are :

  1. $SO _3^{2-}$

  2. $PO _4^{3-}$

  3. $SO _4^{2-}$

  4. $ClO _4^{-}$


Correct Option: B,C,D
Explanation:
Hypervalent molecule -
The hypervalent molecule is a molecule that contains one or more main group elements apparently bearing more than eight electrons in their valence shells.

 Explanation -
A. Valence electrons available in $(SO _3)^{2-}$ => 8
B. Valence electrons available in $(PO _4)^{3-}$ => 10
C. Valence electrons available in $(SO _4)^{2-}$ => 12
D. Valence electrons present  in $(ClO _4)^-$ => 14

Hence B, C, D are hypervalent compounds.

Which one of the following oxoacids of chlorine is the least oxidising in nature ?

  1. $ HClO $

  2. $HClO _2 $

  3. $ HClO _3 $

  4. $HClO _4$


Correct Option: D
Explanation:

$HClO _4$ is the strongest oxidizing agent as the oxidation number of chlorine in $HClO _4$ is +7 and it can't afford to lose any more electron.


It can only gain the electrons which result in oxidation of other species.

Hence, the correct option is $D$

Out of the chloric acid ($\displaystyle { HClO } _{ 3 }$) and perchloric acid ($\displaystyle { HClO } _{ 4 }$), $\displaystyle { HClO } _{ 4 }$ is more stable.


State whether the above statement is true or false.

  1. True

  2. False


Correct Option: A

Which of the following is the correct statement? 

  1. $ SO _2 $ is anhydride of sulphuric acid

  2. $ NO _2 $ is anhydride of nitric acid

  3. $ Cl _2O _7 $ is anhydride of perchoric acid

  4. $ P _2O _5 $ is anhydride of orthophosphorus acid


Correct Option: C
Explanation:
$Cl _2​O _7​+H _2​O⟶2HClO _4​$

Thus $Cl _2​O _7​$ is an anhydride of perchloric acid.

Option C is correct.

Select the correct statement(s) :

  1. The overlap become better when the overlapping orbitals have comparable energy.

  2. The other of increasing tendency of polymerizations $SiO^{4-} _{4}\, >\, PO^{3-} _{4}\, >\, SO^{2-} _{4}\, >\, ClO^{-} _{4}$.

  3. With the increase in positive oxidation state the energy of the 3d-orbitals gradually decreases and it favours the $\pi$-bonding interaction.

  4. The system where the $\pi$ bonding is not effective, the stabilization is attained through the single bonded structure i.e. through the polymerization.


Correct Option: A,B,C,D
Explanation:

The overlap become better when the overlapping orbitals have comparable energy. The extent of overlap between orbitals with huge energy difference is insignificant.

The other of increasing tendency of polymerizations $SiO^{4-} _{4}\, >\, PO^{3-} _{4}\, >\, SO^{2-} _{4}\, >\, ClO^{-} _{4}$. This is the same order in which the electronegativity of the central atom increases.

With the increase in positive oxidation state the energy of the 3d-orbitals gradually decreases and it favors the $\pi$-bonding interaction.

The system where the $\pi$ bonding is not effective, the stabilization is attained through the single bonded structure, i.e., through the polymerization. An example is polymer containing $SiO^{4-} _{4}$ tetrahedra.

Which products are expected from the disproportionation of chlorous acid?

  1. $HClO _3$ and $Cl _2O$

  2. $HClO _2$ and $ HClO$

  3. $HCl $ and $Cl _2O$

  4. $HClO$ and $HClO _3$


Correct Option: D
Explanation:

 Disproportionation reaction of chlorous acid is given as :


$2HClO _2 \rightarrow HClO + HClO _3$

Hence,option D is correct.

The following acids have been arranged in the order of decreasing acid strength. Identify the correct order-
ClOH(I)            BrOH(II)          IOH(III)

  1. I > II > III

  2. II > I > III

  3. III > II > I

  4. I > III > II


Correct Option: A
Explanation:

Higher the I.E, higher the acidic strength of hypohalus acid (hydroxides)

As we move from top to bottom in halogens the I.E will be decreased,so the acidity will be decreased.
The correct oreder of acidity is I > II > III
Hence option A is correct.