Tag: percent and percentage

Questions Related to percent and percentage

$38$ liters of milk was poured into a tub and the tub was found to be $5\%$ empty. To completely fill the tub, what amount of additional milk must be poured?

  1. $1$ litres

  2. $2$ litres

  3. $3$ litres

  4. $4$ litres


Correct Option: B
Explanation:

After pouring $38$ litres of milk, $5\%$ is found empty.
Here $95\%$ of capacity of the tub $= 38$ liters
Therefore, capacity of the tub $= 30\times \dfrac {100}{95} $ litres $= 40$ litres
Thus additional milk to be poured $= (40 - 38) $ i.e., $2$ litres.

$1\%$ of $1\%$ of $25\%$ of $1000$ is :

  1. $0.25$

  2. $0.025$

  3. $0.00025$

  4. $25$


Correct Option: B
Explanation:

We need to find value of $1\%\,\text{of}\,1\%\,\text{of}\,25\%\,\text{of}\,1000$

This would be equal to $\dfrac{1}{100}\times \dfrac{1}{100}\times \dfrac{25}{100}\times 1000$
$=\dfrac{25}{1000}$
$=0.025$.

If $x\%$ of $24=64$, then the value of x is __________.

  1. $\displaystyle 37\frac{1}{2}$

  2. $\displaystyle 133\frac{1}{3}$

  3. $\displaystyle 266\frac{2}{3}$

  4. $\displaystyle 66\frac{2}{3}$


Correct Option: C
Explanation:

$24\times\dfrac{x}{100}=64$

$x=\dfrac{64\times 100}{24}$$=266.667$$=266\dfrac{1}{3}$
Hence the correct answer is option C.

Choose the correct answer from the alternatives given :
A spider climbed $62\frac{1}{2}%$ of the height of the pole in one hour and in the next hour it covered $12\frac{1}{2}%$ of the remaining height. If poles height is 192 m. then distance climbed in second hour is

  1. $3$ m

  2. $5$ m

  3. $7$ m

  4. $9$ m


Correct Option: D
Explanation:

Remaining height = $\left (192 - \dfrac{125}{2}\% of 192 \right ) = $192- 120$ = 72 m$
Required distance (distance covered in second hour) then,
$\dfrac{25}{2}\% of\ 72 $= $\dfrac{25 \times 72}{2 \times 100} = 9 m$

Choose the correct answer from the alternatives given.
Prabhu purchased 30 kg of rice at the rate of Rs. 17.50 per kg and another 30 kg rice at a certain rate. He mixed the variety of two rice and sold the entire quantity at the rate of Rs.18 per kg and made 20% overall profit. At what price per kg did he purchase the lot of another 30 kg rice?

  1. Rs. 14.50

  2. Rs. 12.50

  3. Rs. 15.50

  4. Rs. 13.50


Correct Option: B
Explanation:

Let the price at which the other $30$ kg was bought be Rs. x.
CP of mixture = $\frac{100}{120}\times 18 = 15$
$\frac{2.5}{15 x} = \frac{30}{30}$
$15x=2.5$
Hence, x= Rs. $12.5$

Convert the following percents into fractions:

$\dfrac{1}{2}\%$

  1. $\dfrac{1}{100}$

  2. $\dfrac{2}{100}$

  3. $\dfrac{1}{200}$

  4. $\dfrac{3}{200}$


Correct Option: C
Explanation:

$a\%=\dfrac { a }{ 100 } $ in fraction

$\therefore \dfrac { 1 }{ 2 } \%=\dfrac { 1 }{ 2 } \times \dfrac { 1 }{ 100 } =\dfrac { 1 }{ 200 } $

Convert the following percents into fractions:

$40\dfrac{2}{3}\%$

  1. $\dfrac{61}{50}$

  2. $\dfrac{61}{100}$

  3. $\dfrac{61}{150}$

  4. $\dfrac{183}{150}$


Correct Option: C
Explanation:

$a\%=\dfrac { a }{ 100 } $ in fraction

$40\dfrac { 2 }{ 3 } \%=\dfrac { 122 }{ 3 } \%\ \quad \quad \quad =\dfrac { 122 }{ 3 } \times \dfrac { 1 }{ 100 } \ \quad \quad \quad  =\dfrac { 61 }{ 150 } $

15% of 10% of 20% of 1000 is 

  1. $1.50$

  2. $67$

  3. $150$

  4. $3$


Correct Option: D
Explanation:

$15\%$ of $10\%$ of $20\%$ of $1000$


$\Rightarrow 15\%$ of $10\%\left[\dfrac{20}{100}\times 1000\right]$

$\Rightarrow 15\%$ of $10\%$ of $200$

$\Rightarrow 15\%\left[\dfrac{10}{100}\times 200\right]$

$\Rightarrow 15\%$ of $20$

$\Rightarrow \dfrac{15}{100}\times 20$

$\Rightarrow  3$

$\therefore\ 15\%$ of $10\%$ of $20\%$ of $1000=3$

If $40$%of a number is equal to two-third of another number, what is the ratio of first number to the second numbers?

  1. 2:5

  2. 3:7

  3. 5:3

  4. 7:3


Correct Option: C
Explanation:
$(l-m) (lm+l+x^{2})=0$
 Let the number be $x _{1} y$
Given :- $40\% $ of $(x) = \dfrac{2}{3}$ of $(y)$
to find :-$\dfrac{x}{y}= ?$
$\dfrac{40}{100} \times x = \dfrac{2}{3} \times y$
$\dfrac{x}{y}= \dfrac{2}{3} \times \dfrac{100}{40}$
$\Rightarrow \dfrac{x}{y}= \dfrac{5}{3}$

$5\%$ of $600$

  1. $30$

  2. $60$

  3. $160$

  4. $600$


Correct Option: A
Explanation:

$5\%$ of $600=\dfrac{5}{100}\times 600=5\times 6=30$

Hence, the answer is $30.$