Tag: various mixtures

Questions Related to various mixtures

Which of the following is a true solution?

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. Copper in gold

  2. Sulphur in water

  3. Milk

  4. Water in sulphur dioxide

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Correct Option: A
Explanation:

Copper and gold are melted and mixed together to form an alloy, they form a solid-solid homogeneous mixture,

so, copper in gold is called as true solution.

Which of the following sequences lists the relative sizes of particles in a water mixture from smallest to largest?

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. Solutions, suspensions, colloids

  2. Solutions, colloids, suspensions

  3. Colloids, solutions, suspensions

  4. Colloids, suspensions, solutions

  5. Suspensions, colloids, solutions

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Correct Option: B
Explanation:
The increasing order for the relative particle size is solutions ( 0.1 to 1 ) < colloids  (1 to 1000 ) < suspensions (more than 1000). The numbers in parenthesis refer to particle size in nm.

A solution is defined as a:

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. homogeneous mixture of two or more substances

  2. hetrogeneous mixture of two or more substances

  3. homogeneous mixture of liquid and solid components only

  4. homogeneous mixture consisting of water as one of the components

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Correct Option: A
Explanation:

A solution is a homogeneous mixture of two or more substances. A solution may exist in any phase. For example, in a saline solution, salt is the solute dissolved in water as the solvent.

Describes a solution containing solute particles of intermediate size that do not settle but do scatter light.

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. Miscible

  2. Suspension

  3. Colloid

  4. Saturated

  5. Supersaturated

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Correct Option: C
Explanation:

Colloid particle have a particle size range from 1 to 1000 nanometer and these particles do not settle at the bottom but scatter the light.

Arrange the following in the increasing order of their solubility in n-octane based on solute-solvent interaction: 

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. $KCl < CH _3CN < CH _3OH < Cyclohexane$

  2. $KCl < Cyclohexane < CH _3OH < CH _3CN$

  3. $KCl < CH _3OH < CH _3 CN < Cyclohexane$

  4. $ KCl < Cyclohexane < CH _3CN < CH _3CN$

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Correct Option: C

an organic liquid (A), containing C,H and O with boiling point $78^{\circ}$C and possessing a rather pleasant odour or heating with concenterated $H _{2}SO _{4}$ gives a gaseous product (B) with the empirical formula $CH _{2}$. B decolourises bromine water as well as alkaline $KMnO _{4}$ solution and takes up one mole of $H _{2}$(per mole of B) in the presence of finely divided nickle at high temperature. A and B are:

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. $C _{2}H _{5}OH$, $C _{2}H _{2}$

  2. $CH _{3}OH$, $C _{2}H _{2}$

  3. $C _{2}H _{5}OH$, $C _{2}H _{4}$

  4. $(CH _{3}) _{2}CHOH$, $C _{3}H _{6}$

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Correct Option: C
Explanation:

$C _2H _5OH$ or ethyl alcohol when treated with concentrated $H _2SO _4$ undergoes dehydration to form ethene($C _2H _4$). Ethane reacts with alkaline $KMnO _4$ undergoes oxidation to form ethylene glycol. Ethene  undergoes hydrogenation in presence of nickel heads of one mole of $H _2$ to form ethane.

The correct option is C

A sample of $CH _4$ of 0.08 g was subjected to combustion at $27^oC$ in a bomb calorimeter. The temperature of the calorimeter system was found to be raised by $0.25^oC$. If heat capacity of calorimeter is 18 kJ, $\Delta H$ for combustion of $CH _4$ at $27^oC$ is:

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. $- 900$ kJ/mole

  2. $- 905$ kJ/mole

  3. $- 895$ kJ/mole

  4. $- 890$ kJ/mole

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Correct Option: B
Explanation:

${ CH } _{ 4 }\left( g \right) +{ 2O } _{ 2 }\left( g \right) \longrightarrow { CO } _{ 2 }\left( g \right) +2{ H } _{ 2 }O\left( l \right) $

$\Delta E=$ Heat of combustion
        $=$ Heat capacity $\times$ rise in $T$ $\times$ $\dfrac { Molar\ mass }{ Mass\ of\ compound } $
        $=-18\times 0.25\times \dfrac { 16 }{ 0.08 } $
        $=-900$ KJ/mole                                         $R=8.314\times { 10 }^{ -3 }KJ{ mol }^{ -1 }$
$\Delta H=\Delta E+\Delta nRT$                                      $\Delta n=1-3=-2$
$=-900+\left( -2 \right) \times 8.314\times { 10 }^{ -3 }\times 300$           $T=300K$
$=-900-4.9884=-904.98\simeq -905KJ/mol$

$CoCl _{ 3 }.3NH _{ 3 }$ does not form any precipitate with excess ${ AgNO } _{ 3 }$ solution, whereas 1 mole of $CoCl _{ 3 }.5NH _{ 3 }$ gives two moles of $AgCl$ with excess ${ AgNO } _{ 3 }$. The van't Hoff factor for both the compounds respectively are:

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. 0 and 2

  2. 0 and 3

  3. 1 and 3

  4. 1 and 2

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Correct Option: C
Explanation:

To give ppt with ${ AgNO } _{ 3 }$ solution, a substance has to release ${ Cl }^{ - }$ ions.
$CoCl _{ 3 }.3NH _{ 3 }$ gives no ppt because it does not dissociate in solution.
$\therefore $ Number of particles in solution $=1$ i.e the molecule itself $CoCl _{ 3 }.5NH _{ 3 }$ gives 2 moles $AgCl$ ppt because it dissociate as follows
$CoCl _{ 3 }.5NH _{ 3 }\rightarrow \left[ Co\left( { NH } _{ 3 } \right) _{ 5 }Cl \right] ^{ 2+ }+2{ Cl }^{ - }$
It gives 3 ions on dissociation.
$\therefore $ its van't Hoff factor is 3.

The vapour pressure of two pure liquids A and B are 200 and 400 torr respectively at 300K . A liquid solution (ideal) of A and B for which the mole fraction of A is 0.40 is contained in a cylinder. The composition of components A and B in vapour phase after equilibrium is reached between vapour & liquid phase, respectively is 

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. $X _A = 0.62 ; X _B = 0.38$

  2. $X _A = 0.50 ; X _B = 0.50$

  3. $X _A = 0.25 ; X _B = 0.75$

  4. $X _A = 0.30 ; X _B = 0.70$

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Correct Option: C

When an ideal binary solution is in equilibrium with its vapour, molar ratio of the two components in the solution and in the vapour phases is 

chemistry mix and separate different types of solutions various mixtures introduction to solutions

  1. same

  2. different

  3. may or may not be same depending upon volatile nature of the two components

  4. None of the above

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Correct Option: C
Explanation:
For Solution $A+B$,

$X' _{A}=$ mole fraction of $A$ in vapour  phase

$X' _{A}=\dfrac{X _{A}.P^{0} _{A}}{X _{A}.P^{0}A}$ = can be equal to $X _{A}$ or not which depend on $P^{0} _{A}$ & $P^{0} _{B}$.