Tag: separation methods

Non reacting gases not reacted with each other so they only mix by diffusion.

The mixture of camphor and ammonium chloride cannot be separated by sublimation method since both are volatile substances. Thus the mixture is dissolved in water. Ammonium chloride is soluble in water while camphor is not thus the water containing ammonium chloride is decanted in another beaker. Thus camphor is obtained and now the solution is evaporated to separate ammonium chloride. The solution containing ammonium chloride is heated and boiled off the ammonium chloride is left behind

Sublimation is used to separate a mixture of sand and ammonium chloride. Sublimation is a separation process that entails heating a mixture of solids, where one of the solids transitions from solid to gas without passing through the liquid state. The vaporized solid is then reclaimed by cooling the vapor which reverts back to its initial solid state.

In the case of ammonium chloride and sand, ammonium chloride is the sublimate and changes to vapor

Since crystals of $Y$ were formed on the walls of flask hence it must be some compound which sublimates on heating, and there was no effect on the $X$ so $X$ must be compound with high boiling point. The only combination with these properties are $X=NaCl$, $Y=Naphthalene$

On evaporation of $CuSO _4$ solution, the amount of solvent will decrease and its concentration increases and it will leads to the crystallization of $CuSO _4$.

Odour is the result of the compound vaporising, or at least being a gas, so that your olfactory system is capable of detecting it. If a compound is not so volatile that it vaporises at room temperature, it will not give off an odour.Compounds like methane, benzene etc. that possess covalent bonds are volatile at room temperature hence, gives off smell.

A distinct layer between two liquids will not form when you have a solution that is labelled miscible. A liquid is considered miscible if it can mix with another miscible liquid to form a homogeneous mixture. When heating begins in miscible solutions, vapours will be of both liquids (as miscible solution will give homogeneous mixture in vapour phase as well) with a higher concentration of liquid having low boiling point (since that component will be more volatile in nature).

The correct order of the process would be DFCBAE as shown below.

D.  Place the sand/salt mixture into a beaker and  add water

F.  Stir to allow the salt to dissolve in the water

C.  Filter to remove the insoluble sand

B.  Pour salt water filtrate into an evaporating basin on a tripod over a Bunsen burner

A.  Heat filtrate to evaporate off the solvent (water)

E.  Allow basin to cool & collect salt

A mixture of ammonium chloride and potassium chloride can be separated using the process of sublimation. You must also note that both these substances are sublimable. This technique is quite feasible in this case as the sublimable temperatures of ammonium and potassium chloride differ widely. Between the two, ammonium chloride has lower sublimable temperature. Therefore, it sublimes first followed by potassium chloride.