Tag: fundamental particles of an atom

Questions Related to fundamental particles of an atom

How many moles of electron weighs one kilogram?

chemistry atom fundamental particles of an atom the structure of atoms discovery of subatomic particles

  1. $6.023\times 10^{23}$

  2. $\dfrac {1}{9.108}\times 10^{31}$

  3. $\dfrac {6.023}{9.108}\times 10^{54}$

  4. $\dfrac {1}{9.108\times 6.023}\times 10^8$

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Correct Option: D
Explanation:

Mass of one electron is $9.108\times 10^{-31} kg$.


Mass of one mole of electrons is ${9.108 \times 10^{-31} \times 6.023}\times 10^{23}={9.108\times 6.023}\times 10^{-8}$.

Thus, $1$ kg corresponds to $\dfrac {1}{9.108\times 6.023}\times 10^8$ moles of electrons.

Hence, the correct option is $D$

How many moles of electrons weigh one kilogram? 

(Mass of electron = $\displaystyle 9.108\times 10^{-31}kg $; Avagadro number = $\displaystyle 6.023\times 10^{23}kg $)

chemistry atom fundamental particles of an atom the structure of atoms discovery of subatomic particles

  1. $\displaystyle \frac{1}{9.108\times 6.023}\times 10^{8} $

  2. $\displaystyle 6.023\times 10^{23}$

  3. $\displaystyle \frac{1}{9.108}\times 10^{31}$

  4. $\displaystyle \frac{6.023}{9.108}\times 10^{54}$

Show answer
Correct Option: A
Explanation:

Mass of electron $\displaystyle 9.108\times 10^{-31}kg$.
The number of electrons that weigh 1 kg will be $\frac {1}{\displaystyle 9.108\times 10^{-31}}$
The Avagadro number is $\displaystyle 6.023\times 10^{23}$.    
The number of moles of electrons that weigh 1 kg will be
$\frac {1}{\displaystyle 9.108\times 10^{-31} \times \displaystyle 6.023\times 10^{23}}=\displaystyle \frac{1}{9.108\times 6.023}\times 10^{8}$