Tag: young's double slit experiment

Questions Related to young's double slit experiment

Instead of using two slits, if we use two separate identical sodium lamps in Young's experiment, which of the following will occur?

physics superposition of waves coherence young's double slit experiment interference

  1. General illumination

  2. Widely separate interference

  3. Very bright maxima

  4. Very dark minima

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Correct Option: A
Explanation:

There will be general illumination as super imposing waves do not have constant phase difference.

In Young's double slit experiment, one slit is covered with red filter and another slit is covered by green filter, then interference pattern will be

physics superposition of waves coherence young's double slit experiment interference

  1. red

  2. green

  3. yellow

  4. invisible

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Correct Option: D
Explanation:

When the red and green filters are used, the rays from slits will have wavelengths of red and green light.  The condition of mono chromatic sources will not be met. Hence, the fringe pattern will disappear.

Two sources of light are said to be coherent, when they give light waves of same

physics superposition of waves coherence young's double slit experiment interference

  1. amplitude and phase

  2. wavelength and constant phase difference

  3. intensity and wavelength

  4. phase and speed

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Correct Option: B
Explanation:

In physics, two wave sources are perfectly coherent if they have a constant phase difference and the same frequency (amplitude may be different).

As $c $ be the speed of light which is constant.
Using, $c= \nu \lambda$
Now same $\nu$ gives same $\lambda.$ for the two light sources.
Example: $y _1= A _1 sin wt$  and $y _2=A _2 sin (wt+\phi) $ where $\phi$ is constant.

For interference to take place

physics superposition of waves coherence young's double slit experiment interference

  1. sources must be coherent

  2. sources must have same amplitude

  3. waves should travel in opposite directions

  4. sources must have same frequency

Show answer
Correct Option: A,D
Explanation:

For interference to take place source must be coherent, which implies:

  • Same frequency for the two waves
  • Constant phase difference.
Options A and D match.

To demonstrate the phenomenon of interference, we require two sources which emit radiation of.

physics superposition of waves coherence young's double slit experiment interference

  1. Nearly the same frequency

  2. The same frequency

  3. Different wavelengths

  4. The same frequency and having a definite phase relationship

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Correct Option: D
Explanation:
As for an Interference, Two Sources must be Coherent, hence the two sources must have the same frequency and a definite phase relationship.

A light of wavelength $400\overset{o}{A}$ after travelling a distance of $2\mu m$ produces a phase change of:

physics superposition of waves coherence young's double slit experiment interference

  1. Zero

  2. $3\pi$

  3. $\displaystyle\frac{\pi}{2}$

  4. $\displaystyle\frac{\pi}{3}$

Show answer
Correct Option: A
Explanation:

The number of wavelengths the wave travels is $=\dfrac{l}{\lambda}$ $=\dfrac{2\times 10^{-6}}{400\times 10^{-10}}$ $=50$     which is an integer.

Hence, the point is at a distance which is integral multiple of wavelength.
Thus the phase difference between the points is zero.

To demonstrate the phenomenon of interference of sound, we need:

physics superposition of waves coherence young's double slit experiment interference

  1. two sources, which emit sound of exactly the same frequency

  2. two sources, which emit sound of exactly the same frequency and have a definite phase relationship

  3. two sources, which emit sound of exactly the same frequency and have a varying phase relationship

  4. two sources, which emit sound of exactly the same wavelength

Show answer
Correct Option: B
Explanation:

For demonstration of interference of sound we need two coherent  source, of same frequency with constant phase difference

$P _1=P _{01}  sin  (Kx-\omega t)$

$P _2=P _{02}  sin  (k(x+\Delta x)-\omega t)$

$=P _{02}  sin  (Kx-\omega t+\delta )$

$\delta =K\Delta x=\dfrac{2\pi \Delta x}{\lambda }$

Two coherent sources of intensity ratio $\beta$ interfere. Then the value of $\displaystyle \left( {\frac{{{I _{\max }} - {I _{\min }}}}{{{I _{\max }} + {I _{\min }}}}} \right)$ is:

physics superposition of waves coherence young's double slit experiment interference

  1. $\dfrac{{1 + \beta }}{{\sqrt \beta }}$

  2. $\sqrt {\left( {\dfrac{{1 + \beta }}{\beta }} \right)} $

  3. $\dfrac{{1 + \beta }}{{2\sqrt \beta }}$

  4. $\dfrac{{2\sqrt \beta }}{{1 + \beta }}$

Show answer
Correct Option: D
Explanation:

$\displaystyle \frac{I _2}{I _1}=\beta$                        $\displaystyle \frac{I _{min}}{I _{max}}=\frac{\beta - 2 \sqrt{\beta}+1}{\beta + 2 \sqrt{\beta +1}}$
$\frac{A _2}{A _1} =\sqrt{\beta}$
$\displaystyle \frac{A _2 -A _1}{A _2 + A _1}=\frac{\sqrt{\beta}-1}{\sqrt{\beta}+1}$     $\displaystyle \frac{I _{max}- I _{min}}{I _{max}+ I _{min}}=\frac{(2)}{(2)} \left [ \frac{2 \sqrt{\beta}}{\beta +1}\right ]$

Coherent sources for studies in interference of light are obtained from.

physics superposition of waves coherence young's double slit experiment interference

  1. Two sources derived from a single source of light having a constant phase difference

  2. Two independent sources of light having a varying phase difference

  3. Two independent sources of light having a constant phase difference

  4. None of the above

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Correct Option: A

Interference fringes were produced in Young's double slit experiment using light of wavelength $5000\overset{o}{A}$. When a film of thickness $2.5\times 10^{-3}$cm was placed in front of one of the slits, the fringe pattern shifted by a distance equal to $20$ fringe-widths. The refractive index of the material of the film is?

physics superposition of waves coherence young's double slit experiment interference

  1. $1.25$

  2. $1.35$

  3. $1.4$

  4. $1.5$

Show answer
Correct Option: C
Explanation:

$n\lambda =\left( \mu -1 \right) t$\ $20\times 5\times  { 10 }^{ -7 }=\left( \mu -1 \right) 25\times { 10 }^{ -6 }$\ $\mu =1.4$