Tag: drift velocity and mobility

Questions Related to drift velocity and mobility

The drift velocity of electrons in a conducting wire is of the order of $1:mm/s$, yet the bulb glows very quickly after the switch is put on because

  1. the random speed of electrons is very high of the order of $10^{-6}m/s$

  2. the electrons transfer their energy very quickly through collision.

  3. electric field is set up in the wire very quickly, producing a current through each cross section, almost intantaneously

  4. All the above


Correct Option: C
Explanation:

Drift velocity $v _d= \frac{eEt}{m}$ so drift velocity is directly proportional  to the electric filed. When switch is on, the filed is quick set up wire  and produce current through wire instantaneously.   

A potential difference v exists between the ends of a metal wire of length l. The drift velocity will be doubled if

  1. v is doubled

  2. l is doubled

  3. The diameter of the wire is doubled

  4. The temperature of the wire is doubled


Correct Option: A
Explanation:

The drift velocity is $v _d=\frac{eVt}{2ml}$
The relaxation time t changes with change of temperature. Actually it decreases with rise of temperature. Thus at a given temperature drift velocity  is directly proportional to the potential difference, inversely proportional to length and is independent of cross-sectional area.
So when drift velocity is doubled , V becomes double and l is half.

Assertion : A current flows in a conductor only when there is an electric field within the conductor.


Reason : The drift velocity of electron in presence of electric field decreases.

  1. Both (A) and (R) are true and (R) is the correct explanation of A

  2. Both (A) and (R) are true but (R) is not the correct explanation of A.

  3. (A) is true but (R) is false

  4. (A) is false but (R) is true


Correct Option: C
Explanation:

Current flows when there in P.D.

The presence of P.D implies the presence of Electric field. 
Drift velocity $\propto$ Electric field.

 The electron drift speed is small and the charge of the electron is also small but still, we obtain large current in a conductor. This is due to 

  1. the conducting property of the conductor

  2. the resistance of the conductor is small

  3. the electron number density of the conductor is small

  4. the electron number density of the conductor is enormous


Correct Option: D
Explanation:

Current in the conductor $I = An e v _d$

where $n$ is the number density of free electrons, $v _d$ is the drift velocity of electrons, $e$ is its charge and $A$ is the cross-section area of conductor.
Conductors have very large number density of free electrons, nearly $10^{28}$ $cm^{-3}$, which conduct electric current in the conductor. Thus inspite of having small drift velocity and electronic charge, we obtain large current in the conductor.

Two wires, each of radius r, but of different materials are connected together end to end. If the densities of charge carriers in the two wires are in the ratio 1:4, the ratio of the drift velocity of electrons in the two wires will be . .

  1. 1:2

  2. 2:1

  3. 1:4

  4. 4:1


Correct Option: D
Explanation:

We know that drift velocity is inversely proportional to density of charge carriers.


Hence, ratio of drift velocity is $4:1$.

Answer-(D)

The drift velocity of an electron is doubled if the applied electric field across the conductor is .....

  1. three times

  2. doubled

  3. half

  4. four times


Correct Option: B
Explanation:

The flow of current current is nothing but drift velocity of electrons. Since current is directly proportional to voltage applied, drift velocity of electrons will also be directly proportional to the voltage applied. And it follows Ohm's law as V = I/R. So, if voltage is doubled, current is doubled and hence the drift velocity is doubled.

When there is an electric current through a conducting wire along its length then an electric field must exist

  1. inside the wire but normal to it

  2. inside the wire but parallel to it

  3. outside the wire but normal to it

  4. outside the wire but parallel to it


Correct Option: B
Explanation:

As current is flowing through it , it means charges are flowing along its length therefore heir must be some electric field parallel to the length of the wire. Hence correct option is B.

Copper contains $8.4\times 10^{28}$ free electrons$/m^3$. A copper wire of cross-sectional area $7.4\times 10^{-7}m^2$ carries a current of $1$A. The electron drift speed is approximately.

  1. $10^{-8}$m/s

  2. $10^3$m/s

  3. $1$m/s

  4. $10^{-3}$m/s


Correct Option: D
Explanation:

$v=\dfrac{I}{ne}=\dfrac{1}{7.4\times 10^{-7}}\times 8.4\times 10^{28}$
$=\dfrac{10^{-2}}{8.4\times 1.6\times 7.4}=10^-3$.

Drift velocity varies with the intensity of electric field as per the relation

  1. ${v} _{d}\propto E$

  2. ${v} _{d}\propto \cfrac{1}{E}$

  3. ${v} _{d}=$ constant

  4. ${v} _{d}\propto {E}^{2}$


Correct Option: A
Explanation:

Current , $I$ = $neAv _{d} $

Current density , $J$ = $\frac{I}{A}$ = $nev _{d} $
Also , current density $J$ is related to electric field $E$
by the relation 
$J = \sigma E$
Therefore , 
$nev _{d}$ = $J = \sigma E$
Hence , $v _{d}  \alpha E$ .

a current 10 ampere is maintained in a conductor of cross section of $ 10^{-4}m^2 $. if the electron density is $ 9 \times 10^{28} m^{-3} $ , what is the drift velocity of free electrons?

  1. $ 6.9 \times 10^{-6} ms^{-1} $

  2. $ 6.9 \times 10^{-4} ms^{-1} $

  3. $ 6.9 \times 10^{5} ms^{-1} $

  4. none of thses


Correct Option: A