Tag: semicircle and ring

Questions Related to semicircle and ring

The diameter of a wheel is 98 cm The number of revolutions it will have to cover a distance of 1540 m is

  1. 500

  2. 600

  3. 700

  4. 800


Correct Option: A
Explanation:

Given the diameter of wheel is 98 cm

Then radius of wheel =$\frac{98}{2}=49cm$
Then circumference of wheel =$2\times \frac{22}{7}\times 49=308cm$
Then the number of revolution in distance of 1540 m=$\frac{1540\times 100}{308}=\frac{154000}{308}=500$

What is the area of the circular ring included between two concentric circles of radius $14$ cm and $10.5$ cm ? 

  1. $255 cm^2$.

  2. $148 cm^2$.

  3. $324 cm^2$.

  4. $269 cm^2$.


Correct Option: D
Explanation:

 Area of the circular ring = $\frac { 22 }{ 7 } \times \left( { R }^{ 2 } - { r }^{ 2 } \right)$ = $ \frac { 22 }{ 7 } \times \left( { 14 }^{ 2 } - { 10.5 }^{ 2 } \right)$ = $269.5 \ { cm }^{ 2 }\approx 269\ { cm }^{ 2 } $

If the outer and inner radii of a ring are $10$ cm and $8$ cm, then its area is nearly

  1. $113.443$ sq. cm

  2. $113.343$ sq. cm

  3. $113.243$ sq. cm

  4. $113.143$ sq. cm


Correct Option: D
Explanation:

$Area=\pi (100^{2} - 8^{2}) = \pi 36 = 113.143\ cm^{2}$.

Find the area of a ring shaped region enclosed between two concentric circles of radii $20$ cm and $15$ cm.

  1. $175\pi cm^2$

  2. $75\pi cm^2$

  3. $275\pi cm^2$

  4. $750\pi cm^2$


Correct Option: A
Explanation:
$x=1$ 
$r _{1}=20cm$ 
$r _{2}=15cm$
 $Area = \pi (r _{2}^{2}-r _{1}^{2})$ 
$^{2}\pi ((20)^{2}-(15)^{2})$ 
$\pi (400-225)$ 
$=775\pi cm^{2}$

A lawn is in the shape of a semi-circle of diameter $35$ $dm$. The lawn is surrounded by a flower- bed of width $3.5\ dm$ all around. Find the area of the flower bed in $d m ^ { 2 }$.

  1. $407.8895$

  2. $403.8825$

  3. $407.2343$

  4. $409.2543$


Correct Option: B

A semicircle of diameter 2 is drawn. Two point on the semicircle are chosen so that they are 1 unit apart. A  semicircle of diameter 1 is the drawn with those two point as the 'endpoints' . The shaded area inside this smaller semicircle and outside the larger semicircle is called a lune. Determine the area of this lune.

  1. $\frac{\pi }{6} - \frac{{\sqrt 3 }}{4}$

  2. $\frac{{\sqrt 3 }}{4} - \frac{\pi }{{12}}$

  3. $\frac{{\sqrt 3 }}{4} - \frac{\pi }{{24}}$

  4. $\frac{{\sqrt 3 }}{4} + \frac{\pi }{{24}}$


Correct Option: B

In a triangle with sides $a$, $b$, and $c$, a semicircle touching the sides $AC$ and $CB$ is inscribed whose diameter lies on $AB$. Then the radius of the semicircle is

  1. $a/2$

  2. $\triangle/s$

  3. $\dfrac{2\triangle}{a+b}$

  4. $\dfrac{2\ abc}{(s)(a+b)}\cos\dfrac{A}{2}\cos\dfrac{B}{2}\cos\dfrac{C}{2}


Correct Option: A

measure of angle inscribed in a semicircle is 

  1. ${90}^{0} $

  2. ${120}^{0} $

  3. ${100}^{0} $

  4. ${60}^{0} $


Correct Option: A
Explanation:
The intercepted arc for an angle inscribed in a semi-circle is $180^{\circ}$. 

Therefore the measure of the angle should be half of $180^{\circ}$, or $90^{\circ}$. 

The angle is a right angle.

Points $P,Q,R$ lie on same line. Three semi circles with the diameters $PQ,QR,PR$ are drawn on same side of line segment $PR$. The centres of the semicircles are $A,B,O$ respectively. A circle with centre $C$ touches all $3$ semi circles then the radius of this circle is $\left(AQ=a,BQ=b\right)$

  1. $\dfrac{ab}{a+b}$

  2. $\dfrac{ab\left(a+b\right)}{a^{2}+b^{2}}$

  3. $\dfrac{ab\left(a+b\right)}{a^{2}+ab+b^{2}}$

  4. $\dfrac{ab\left(a+b\right)}{\left(a-b\right)^{2}}$


Correct Option: A

In a triangle with sides a, b, and c, a semicircle touching the sides AC and CB is inscribed whose diameter lies on AB. Then, the radius of the semicircle is 

  1. a/2

  2. $\Delta /s$

  3. $\frac { 2\Delta }{ a+b } $

  4. $\frac { 2abc }{ (s)(a+b) } cos\frac { A }{ 2 } cos\frac { B }{ 2 } cos\frac { C }{ 2 } $


Correct Option: A