Tag: group 17 elements - properties

Questions Related to group 17 elements - properties

________ form negative ions in an ionic bond.

  1. Alkali metals

  2. Alkaline earth metals

  3. Noble gases

  4. Halogens


Correct Option: D
Explanation:
As halogen are most electronegative and have a high tendency to gain electrons they form negative ions in an ionic bond.
Hence option $D$ is correct.

Statement $1$: Element $Z$ with an electronic configuration of $1s^{2} 2s^{2} 2p^{5}$ can be expected to form the compound $MgZ _{2}$.
Statement $2$: Each atom of $Z$ needs two electrons to fill its valence shell.

  1. Both Statement $1$ and Statement $2$ are correct and Statement 2 is the correct explanation of Statement $1$

  2. Both Statement $1$ and Statement $2$ are correct, but Statement $2$ is NOT the correct explanation of Statement $1$

  3. Statement $1$ is correct, but Statement $2$ is not correct

  4. Statement $1$ is not correct, but Statement $2$ is correct


Correct Option: C
Explanation:

Element Z has electronic configuration ${1s}^2 2s^2 2p^{5}$ , its belongs to 17th group so, it can form compound $MgZ _2$.

Its valency will be one.
It requires 9 elctron to fill its valence shell or it has already 9 electrons. So, statement 2 is wrong.
 

Treatment of the dry solid with a mild oxidizing agent produces a purple solid having formula _______.

  1. $N _2$

  2. $KI$

  3. $CCl _4$

  4. $AgNO _3$


Correct Option: B
Explanation:

Iodine can be displaced from potassium iodide if a more reactive element is made to react with potassium iodide. In the presence of a mild oxidising agent, the iodine ions are oxidised to $I _2$. Iodine is purple in colour.

Identify the gas that would form when hydrobromic acid is combined with nickel (II) sulfide.

  1. $NiBr _{2}$

  2. $H _{2}S$

  3. $HBr$

  4. $NiS$


Correct Option: B
Explanation:

The gas that would form when hydrobromic acid is combined with nickel (II) sulfide is $H _2S$

$2 HBr(aq) + NiS(s)\rightarrow H _2S + NiBr _2$.
Hence option B is correct.

When $KClO _3$ is heated in presence $MnO _2$ the product is:

  1. $O _2$

  2. $Cl _2$

  3. $O _3$

  4. none of these


Correct Option: A
Explanation:

When $KClO _3$ is reacted with $MnO _2$ in presence of heat it forms $KCl,O _2,MnO _2$ respectively.

$KClO _3+MnO _2\longrightarrow KCl+O _2+MnO _2$

Hence option A is correct.

Which of the following is most acidic?

  1. $HClO$

  2. $HClO _2$

  3. $HClO _3$

  4. $HClO _4$


Correct Option: D
Explanation:

As the oxidation number of chlorine(non metal) increases in the given acids the acidic nature of the compound increases. So the oxidation numbers of chlorine in the given compounds are $+1,+3,5,+7$ respectively.

So the acidic nature of $HClO _4$ is high.
Hence option D is correct.

A one litre flask is full of brown bromine vapour. Intensity of brown colour vapour will not decrease a appreciable amount on adding to flask some of:

  1. Piece of marble

  2. Carbon disulphide

  3. Carbon tetrachloride

  4. Animal charcoal powder


Correct Option: A
Explanation:

A one litre flask is full of brown bromine vapour. Intensity of brown colour vapour will not decrease a appreciable amount on adding to flask some of Piece of marble.

Hence option A is correct.

Fluorine is stronger oxidising agent than chlorine in water. The factor which is not responsible for that:

  1. Heat of dissociation

  2. e-affinity

  3. Heat of hydration

  4. Ionisation potential


Correct Option: B
Explanation:

Affinity do not have any relation with the efficiency of oxidizing ability.

Hence option A is correct.

$Br _2$ turns starch iodide paper :

  1. blue

  2. red

  3. colourless

  4. yellow


Correct Option: A
Explanation:

The bromine releases iodine from the potassium iodide Iodine reacts with starch to produce a blue color.

$Br _2+KI\rightarrow KBr+I _2$

Hence option A is correct

Which of the following reactions are not possible?

  1. $2NaCl+F _2$ $\longrightarrow \ $ $2NaF+Cl _2$

  2. $2NaCl+Br _2$ $\longrightarrow \ $ $2NaBr+Cl _2$

  3. $2NaF+Cl _2$ $\longrightarrow \ $ $2NaCl+F _2$

  4. $2NaBr+Cl _2$ $\longrightarrow \ $ $2NaCl+Br _2$


Correct Option: B,C
Explanation:

Option B and C reactions are not possible because the bromine do not displace chlorine and chlorine do not displace florine as chlorine and florine are most stable than bromine and chorine in their compounds respectively.

Hence option B,C are correct.