Tag: coordinate bond

Questions Related to coordinate bond


Dative bond is present in the molecule :

  1. $NH _3$

  2. $CO _2$

  3. $NaCl$

  4. None of these.


Correct Option: D
Explanation:
A dative bond is a covalent bond between two atoms where one of the atoms provides both electrons that form the bond i.e. a kind of 2-center, 2-electron bond.

Here, covalent bond is present in $NH _3$ and $CO _2$, whereas ionic bond is present in $NaCl$.

So, there is no dative bond in  $NH _3$, $CO _2$ and $NaCl$.

Hence, option (D) is the correct answer.

If pure $'p'$ orbitals are involved in molecule formation, then the shape of ${ H } _{ 3 }{ O }^{ + }$ will be:

  1. pyramidal

  2. tetrahedral

  3. angular

  4. planar


Correct Option: A
Explanation:

$ H _3O^+$ will have three bond pairs and one lone pair and shape same as $NH _3$ is therefore pyramidal. The hydroxonium ion is isoelectronic with ammonia and has an identical shape of pyramidal. 

So option $A$ is the correct option. 

The dative bond is present in:

  1. $NH _{3}$

  2. $NH _{4}Cl$

  3. $PCl _{5}$

  4. $BF _{3}$


Correct Option: A
Explanation:

When ammonium is formed, the fourth hydrogen is formed is attached by dative covalent bond because the only hydrogen nucleus is transferred from chlorine to nitrogen. The hydrogen electron left behind on the chlorine to form the negative chloride ion.

Which of the following property is commonly exhibited by a covalent compound?

  1. High solubility in water

  2. Low melting point

  3. High electrical conductance

  4. High boiling point


Correct Option: B
Explanation:

Covalent compounds are very resistant, they do not conduct heat and electricity, mostly insulators. They have low boiling points as they are gases at room temperature. It is very hard to molten the covalent compounds because of high bond energy. Therefore the covalent compound turns liquid from solid state easily. They show low melting points and are non polar hence insoluble in water.

"Hybridisation of central atom does not always change due to back bonding". This statement is valid for which of the following compounds ? 
(i) $CCl^- _3$                      (ii) $CCl _2$
(iii) $(SiH _3) _2 O$              (iv) $N(SiH _3) _3$

  1. (i), (ii)

  2. (i), (iii)

  3. (ii), (iii)

  4. All


Correct Option: A
Explanation:

When there is back bonding from central to side atom change in hybridization takes place. Back bonding takes place when one atom has vacant orbital and one has lone pairs. 
So central atom has a lone pair and side atom must have vacant orbital 
So : $CCl^- _3$
$N (SiH _3) _3$
$Sp^3 - Sp^2$

Which of the following compound has coordinate (dative) bond :

  1. $CH _3NC$

  2. $CH _3OH$

  3. $CH _3Cl$

  4. $NH _3$


Correct Option: D

Dative bond is present in ____________.

  1. Carbon monoxide

  2. Carbon dioxide

  3. Nitric oxide

  4. Dichlorine monoxide


Correct Option: A,C
Explanation:

Carbon monoxide and nitric oxide contains dative bond or coordinate covalent bond whereas carbon dioxide and dichlorine monoxide contains covalent bonds.

Which of the following molecules does not have co-ordinate bonds?

  1. $PH _{4}^{+}$

  2. $NO _2$

  3. $O _3$

  4. $CO _{3}^{2-}$


Correct Option: D

In the cyanide, the negative charge is on :

  1. $C$

  2. $N$

  3. both $C$ and $N$

  4. resonate between $C$ and $N$


Correct Option: A
Explanation:

Hetrolytic bond dissociation of $HCN$:
$H-CN\rightarrow H^++ ^-C\equiv N$.
So here, negative charge is on $C$.

Which of the following does not have coordinate bond? 

  1. $S{O _2}$

  2. $HN{O _3}$

  3. ${H _2}S{O _3}$`

  4. $HN{O _2}$


Correct Option: B