Tag: law of multiple proportion

Questions Related to law of multiple proportion

An elements forms two oxides containing respectively 53.33 and 36.36 percent of oxygen. These figures illustrate the law of :

  1. Conservation of mass

  2. Constant proportions

  3. Reciprocal proportions

  4. Multiple proportions


Correct Option: D
Explanation:

An element forms to oxides containing different percentages of oxygen this illustrates that a fixed mass of the elements combine to give more than one compound then they would do so in a simple whole number ratio. Hence this illustrates law of multiple proportions.

Among the following pairs,the one which illustrates the law of multiple proportions is_____.

  1. $NH _3, \ HCl$

  2.  ${ H } _{ 2 }S,{ SO } _{ 2 }$

  3. $CuO,{ Cu } _{ 2 }O$

  4. ${ CS } _{ 2 },{ FeSO } _{ 4 }$


Correct Option: C

A hybrid rocket propellant uses:

  1. a liquid oxidizer and a solid fuel 

  2. a complete solid propellent

  3. a beleqiud propellent

  4. None of the above


Correct Option: A
Explanation:
Hybrid propellant engines represent an intermediate group between solid and liquid propellant engines. One of the substances is solid, usually the fuel, while the other, usually the oxidizer, is liquid. 

The liquid is injected into the solid, whose fuel reservoir also serves as the combustion chamber. The main advantage of such engines is that they have high performance, similar to that of solid propellants, but the combustion can be moderated, stopped, or even restarted. It is difficult to make use of this concept for vary large thrusts, and thus, hybrid propellant engines are rarely built.

A hybrid engine burning nitrous oxide as the liquid oxidizer and HTPB rubber as the solid fuel powered the vehicle SpaceShipOne, which won the Ansari X-Prize.

Hence, the correct option is $\text{A}$

Which of the following pairs of compound illustrate law of multiple proportions ?

  1. KOH, CsOH

  2. $ H _2O, D _2O $

  3. Ethane , benzene

  4. KCI, KBr


Correct Option: C

$i$. Percentage of $Mg$ in $MgO$ and $MgCl _{2}$ 

$ii$. Percentage of $C$ in $CO$ and $CO _{2}$
$iii$. Percentage of $Cr$ in $K _{2} Cr _{2}O _{7}$ and $K _{2}CrO _{4}$ 
$iv$. Percentage of $Cu$ isotopes in $Cu$ metal
The law of multiple proportions may be illustrated by data given by:

  1. $ii$

  2. $iv$

  3. $i$ and $ii $

  4. $i,\ ii$ and $iii$


Correct Option: A
Explanation:

According to law of multiple proportion, if two elements combine to form more than one compound, then the weight of one element combining with the fixed weight of other, in the two compounds, is in a whole number ratio.

Law of multiple proportions is not applicable for the oxides (s) of __________.

  1. carbon

  2. iron

  3. nitrogen

  4. aluminium


Correct Option: D
Explanation:
Law of multiple proportions

If two elements chemically combine to give two or more compounds, then the weight of one element which combines with the fixed weight of the other element in those compound bear a simple multiple ratios to one another.

Eg: Nitrogen forms the oxides- $N _2O, NO, N _2O _3, NO _2, N _2O _5$

But aluminium form only 1 type of oxide $Al _2O _3$.

The oxides of a certain (hypothetical) element contain 27.28 %, 42.86% and 52.94% oxygen. What is the ratio of the valances of the element in the 3 oxides? 

  1. 2 : 3 : 4

  2. 1 : 3 : 4

  3. 1 : 2 : 4

  4. 1 : 2 : 3


Correct Option: D

$CO,CO _2, C _2O _3$ follows :

  1. law of definite proportion

  2. law of multiple proportion

  3. law of conservation of mass

  4. all of the above


Correct Option: B
Explanation:

The Law of Multiple Proportion: It was given by Dalton. When one element combines with the other element to form two or more different compounds, the mass of one elements, which combines with a constant mass of the other, bear a simple ratio to one another.
So, 
$CO,CO _2, C _2O _3$ follows law of multiple proportion.

The composition (by atoms) of compound A is $40$% X and $60$% Y. The composition (by atoms) of compound B is $25$% X and $75$% Y. According to the law of multiple proportions, the ratio of the weight of element Y in compounds A and B is:

  1. $1 : 2$

  2. $2 : 1$

  3. $2 : 3$

  4. $3 : 4$


Correct Option: A
Explanation:
The composition of compound A is  $X:Y = 40:60= 2:3$
The composition of compound B is $X:Y= 25:75= 1:3$

According to the law of multiple proportions, 
In compound A $2$ moles of $X$ bind with $3$ moles of $Y$.
In compound B $2$ moles of $X$ bind with 6 moles of $Y$ 

The ratio of the weight of element $Y$, in combining with a fixed number of $X$ atoms, in these two compounds $A$ and $B$ is $ 3:6 = 1 : 2$.

In $SO _{2}$ and $SO _{3}$, the ratio of weight of oxygen that combines with a fixed weight of sulphur is $2 : 3$. This illustrates the law of:

  1. constant proportions

  2. conservation of mass

  3. multiple proportions

  4. reciprocal proportions


Correct Option: C
Explanation:

The law of multiple proportions says that If two elements form more than one compounds between them, then the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.