Tag: study of heavy water

Questions Related to study of heavy water

Heavy water is used as:

  1. drinking water

  2. detergent

  3. washing water

  4. a moderator


Correct Option: D
Explanation:

In nuclear reactors, heavy water is used as moderator for neutrons.

Heavy water $(D _{2}O)$ freezes at ?

  1. $-3.8^{0}C$

  2. $3.8^{0}C$

  3. $0^{0}C$

  4. $38^{0}C$


Correct Option: B
Explanation:
The freezing point of heavy water is $3.8^{0}C $ or $276.8 K$. The boiling point is $101.4^{0}C $ or $374.4 K$.

Which compound is formed when calcium carbide reacts with heavy water?

  1. $C _{2}D _{2}$

  2. $CaD _{2}$

  3. $CD _{2}$

  4. $Ca _{2}d _{2}$


Correct Option: A
Explanation:
When calcium carbide reacts with heavy water, deuterated acetylene ($C _{2}D _{2}$) is formed.
$CaC _{2} + 2D _{2}O \rightarrow C _{2}D _{2} + Ca(OD) _{2}$

If a mole of hydrogen molecule is heated to a high temoerature then which of the following reactions take place?

  1. $H _2{(g)} + 436 kJ mol^{-1} \rightarrow H{(g)} + H{(g)}$

  2. $2H2{(g)} + 820 kJ mol^{-1} \rightarrow 2H _2{(g)}$

  3. $H _2{(g)} + H _2{(g)} + 436kJ mol^{-1} \rightarrow H^{+} _{(aq)} + H^{-} _{(aq)}$

  4. $H _2{(g)} + 200kJ mol^{-1} \rightarrow H _{(g)} + H _{(g)}$


Correct Option: A
Explanation:

The amount of energy required to break $H-H$ bond of 1 mole of gaseous hydrogen is 436 $kJ \ mol^{-1}$. This is known as bond dissociation enthalpy.
$H _2{(g)} + 436 \  kJ mol^{-1} \rightarrow  H{(g)} + H{(g)}$

Some of the major uses of heavy water are given below. Which one is not correct?

  1. It is used as a moderator in nuclear.

  2. It is used as a tracer compound for studying reaction mechanism

  3. High concentration of heavy water accelerates the growth of plants

  4. It is used in preparing deuterium


Correct Option: C
Explanation:

High concentration of heavy water retards the growth of the plants. Tobacco seeds do not grow in heavy water.

What is heavy water?

  1. $H _{2}O^{18}$

  2. $D _{2}O$

  3. $H _{2}O^{17}$

  4. $H_{2}O


Correct Option: B
Explanation:

Deuterium oxide $D _{2}O$ is known as heavy water. When both $H$ atoms of water $(H _2O)$ are replaced with $D$ atoms, heavy water is obtained.

Calcium carbide + heavy water $\rightarrow$ ?
The product of the above reaction is:

  1. $C _2H _2$

  2. $CaD _2$

  3. $Ca(OD) _2$

  4. $CD _4$


Correct Option: C
Explanation:

$CaC _{2}+2D _{2}o\rightarrow Ca(OD) _{2}+C _{2}D _{2}$

$D _2O$ can be obtained by:

  1. repeated distillation

  2. exchange process

  3. neutron emitting radioactive decay in presence of water

  4. exhaustive electrolysis of alkaline water


Correct Option: A,B,D
Explanation:

Heavy water is deuterium oxide $(D _2O)$. Ordinary water contains a fraction (1 in 6000 parts) of heavy water. On large scale, it is produced by repeated electrolysis of ordinary water containing alkali. It is also produced by repeated distillation and condensation. It is also obtained by exchange process.

Heavy water is used as a:

  1. fuel in engines

  2. semiconductor

  3. moderator in nuclear reactors

  4. insulator in steam engines


Correct Option: C
Explanation:

Heavy metals is used as a moderator in nuclear reactors to bring the fission reaction by slowing down the neutrons and capturing them. The main reason is that the heavy water captures less neutrons than the normal water. Later it can be used as a fuel which has not undergone enrichment to increase the percentage of Uranium-235

$D _{2}O$ is used more in:

  1. chemical industry

  2. nuclear moderator

  3. pharmaceutical preparation

  4. insecticide preparations


Correct Option: B
Explanation:

Heavy water is used in nuclear reactors, where it acts as a neutron moderator to slow down neutrons so that they are more likely to react with the fissile uranium-235 than with uranium-238, which captures neutrons without fissioning.