Tag: thin lens

Questions Related to thin lens

A convex lens of focal length 10 cm is being placed in contact with a concave lens of focal length 20 cm. The focal length of the combination is.

  1. -20 cm

  2. 20 cm

  3. 10 cm

  4. -10 cm


Correct Option: B

A point object is placed at a distance of $15 cm$ from a convex lens. The image is formed on the other side at a distance of $30cm$ from the lens. When a concave lens is placed in contact with the convex lens, the image shifts away further by $30 cm$. Calculate the focal lengths of the concave and convex lenses.

  1. $10 cm, 60 cm$

  2. $ 20 cm, 30 cm$

  3. $60 cm, 10 cm$

  4. $30 cm, 20 cm$


Correct Option: C

Two plano-convex lenses of glass of refractive index $1.5$ have radii of curvature $20\ cm$ and $30\ cm$. They are placed in contact with curved surfaces towards each other and the space between them is filled with a liquid of refractive index $4/3$. The focal length of the combination is

  1. $48\ cm$

  2. $72\ cm$

  3. $12\ cm$

  4. $28\ cm$


Correct Option: B

An achromatic combination of a concave and convex lenses  has power 5D. If the power of convex lens is 4 D then the magnitue of focal length of concave lens is 

  1. 10 cm

  2. 200 cm

  3. 100 cm

  4. 20 cm


Correct Option: B

Two lenses  of power  6 D and -2D are combined  to form a single lens.  The focal length of  this  lens will be 

  1. $\frac{3}{2}m$

  2. $\frac{1}{4}m$

  3. 4 m

  4. $\frac{1}{8}m$


Correct Option: C

A convex lens of focal length 40 cm is in contact with a concave lens of focal length 25 cm. The power of the combination is :

  1. -1.5 dioptres

  2. -6.5 dioptres

  3. +6.5 dioptres

  4. +6.67 dioptres


Correct Option: A

A convex lens is in contact with a concave lens. The magnitude of the ratio of their focal lengths is 2/3. Their equivalent focal length is 30 cm. What are their individual focal lengths?

  1. -15, 10

  2. -10, 15

  3. 75, 50

  4. -75, 50


Correct Option: A
Explanation:

Let focal length of convex lens be $f$


Then focal length of the concave lens $ =  - 1.5f$


Equivalent focal length $ =  \dfrac{- 1.5 f \times f }{ (-0.5f) }= 3f$
 
=>$ f = 10 cm$

So individual focal lengths are 10 cm and -15 cm

A convex lens of focal length $f _1$ and a concave lens of focal length $f _2$ are placed in contact. The focal length of the combination is

  1. $(f _1 + f _2)$

  2. $(f _1 - f _2)$

  3. $\displaystyle \frac{f _1 f _2}{f _2 - f _1}$

  4. $\displaystyle \frac{f _1 f _2}{f _2 + f _1}$


Correct Option: C
Explanation:

$\displaystyle \frac{1}{f} = \frac{1}{f _1}+ \frac{1}{- f _2} = \frac{f _2 - f _1}{f _1 f _2} ;        f = \frac{f _1f _2}{f _2 - f _1}$

A lens of power +2 diopter is placed in contact with a lens of power -1 diopter. The combination will behave like

  1. a convergent lens of focal length 50 cm

  2. a divergent lens of focal length 100 cm

  3. a convergent lens of focal length 100 cm

  4. a convergent lens of focal length 200 cm


Correct Option: C
Explanation:

$P = P _1 + P _2 = + 2 - 1 = +1$ diopter, lens behaves as convergent
$F = \displaystyle \frac{1}{P} = \frac{1}{1} = 1m = 100 cm$

The radius of curvature of the convex surface of a plano-convex lens is $10 cm$. What is the focal length of the plano-convex lens? (Here $\displaystyle \mu $ = $1.5$) 

  1. $10 cm$

  2. $20 cm$

  3. $15 cm$

  4. $5 cm$


Correct Option: B
Explanation:

$\mu=1.5 , R _1=10cm , R _2=0$


As focal length is given by $\dfrac{1}{f}=(\mu-1)(\dfrac{1}{R _1}-\dfrac{1}{R _2})$  (lens maker formula)

$\dfrac{1}{f}=0.5\times (\dfrac{1}{10}-0)$

$f=20cm$

hence, the focal length of the plano-convex lens is $20cm$.