Tag: photosystems
Questions Related to photosystems
Evidence for the liberation of O$ _2$ from water during photosynthesis comes from
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Release of $^{18}$O if water contains the same
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Isolated chloroplast supplied with reducing agent like potassium ferrocyanide evolves O$ _2$ even in absence of CO$ _2$
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Photosynthetic bacteria do not Iiberate O$ _2$ and they use H$ _2$S for obtaining reducing power
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All of the above
A. Ruben and Kamen used the radioactive isotope of oxygen ($^1$$^8$O) in water and found that O$ _2$ liberated in the process was isotopically labelled. On the contrary, when $^1$$^8$O in CO$ _2$ was used, the evolved O$ _2$ did not show radioactivity.
A specific function of light in the process of photosynthesis is
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Reduction of $CO _2$
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Activate other molecules
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Split water molecules
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None of the above.
Photolysis of water means splitting of water in the presence of light to get $H^+$ nascent oxygen and electron that compensate the loss of an electron from PS II during Z scheme and oxygen is released a the by-product with $H^+$ that acts as a proton and collects in the stroma.
In photosynthesis, photolysis of water is used in
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Reduction of NADP$^+$
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Oxidation of NADP
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Oxidation of FAD
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None of the above
Photolysis of water is mainly carried out to compensate the electrons that are transferred to photosystem I by photosystem II during the non-cyclic photophosphorylation that reduce NADP$^+$ into NADPH.
Photolysis of water requires
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Light
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Chlorophyll
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Both A and B
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Electron transport
A) As the name suggests, photolysis of water requires light.
So the correct answer is 'Both A and B'.
Which of the following provides electrons for reduction reactions in photosynthesis?
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NADPH
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Chlorophyll
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Cytochrome
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Water
Photolysis of water: Occurs at grana i.e., lumen side of grana thylakoid membrane with the help of water splitting complex or OEC (oxygen evolving complex). This step is associated with PS- II of Z- scheme.
$2H _2O\rightarrow4{H}^++ O _2+4{e}^-$
It is believed that oxygen evolves as oxygen gas, electrons are accepted by PS II reaction centre through unknown substance and hydrogen ions temporarily stay in the thylakoid space.
Hence, the correct answer is 'Water'.
Four electrons produced during photolysis of water will enter
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PS I
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PQ
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PS II
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PC
- The photolysis of water (H$ _2$O) in the light reactions of photosynthesis occurs in the water-splitting complex of photosystem II.
- photosystem II in thylakoid membranes of chloroplasts where light is used to split water molecules as represented by the following equation: 2H$ _2$O → 4H+ + 4e- + O$ _2$.
- Oxygen (O$ _2$) is liberated to the atmosphere as a waste product in this process and the electrons (e-) are gained to replace those lost through photoexcitation from chlorophyll a in the reaction center of photosystem II which begins noncyclic photophosphorylation. Hence four electrons produced during photolysis of water will enter PS II.
- So, the correct answer is 'PS II'.
In photosynthesis, splitting of water occurs during
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Cyclic photophosphorylation
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Non-cyclic photophosphorylation
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Oxidative photophosphorylation
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Calvin cycle
Photolysis of a water molecule yields
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2 electrons and 4 protons
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4 electrons and 4 protons
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4 electrons and 2 protons
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2 electrons and 2 protons
Photolysis is part of the light-dependent reactions of photosynthesis. The general reaction of photosynthetic photolysis can be given as
H2AH2A + 2 photons (light) → 2 e−e− + 2 H+H+ + A
So, the correct option is 'Option D'.
Minerals involved in photolysis are
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Mg and CI
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K and Mn
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Mo and Mn
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Mn and Cl
A) Mg is responsible for the activation of many enzymes, but is not involved in photolysis. Cl ions help in the photolysis of water.
Extrusion of electron from reaction centre of PS II leaves a hole which is filled by electron released from
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$H _2O$
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$CO _2$
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Chlorophyll
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Light
Non-cyclic phosphorylation involves both Photosystem I and Photosystem II. These two photosystems work in series, first PS II and then PS I. The two photosystems are connected through an electron transport chain. $NADPH$ is synthesized by this kind of electron flow. Electrons are transferred from the PS II and then passed on to the pigments of PS I. Then, electrons get excited and transferred to another acceptor. These electrons are then moved downhill again to a molecule of $NADP^{+}$. The addition of these electrons results in the formation of $NADPH$. Extrusion of the electron from reaction centre of PS II leaves a hole which is filled by electron released from $H _{2}O$. This is achieved by electrons available due to the splitting of water. The water splitting complex is associated with PS II, which itself is physically located on the inner side of the membrane of the thylakoid. Water is split into $H^{+}$, $O$ and electrons. The protons and oxygen formed by splitting of water is released within the lumen of the thylakoids. The oxygen produced is released as one of the net products of photosynthesis.