Tag: structure of human eye

Questions Related to structure of human eye

Long-sighted people who have lost their spectacles can still read a book by looking through a small (3-4 mm) hole in a sheet of paper :

structure of human eye human eye and colourful world

  1. Because the fine hole produces an image of the letters at a longer distance

  2. Because in doing so the distance of the object is increased

  3. Because in doing so the focal length of the eye lens is effectively decreased

  4. Because in doing so the focal length of the eye lens is effectively increased

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Correct Option: C
Explanation:

Long-sighted people who have lost there spectacles can still read a book by looking through a small (3-4 mm) hole in a sheet of paper because by doing so due to the diffraction at the hole the focal length of the eye lens is effectively decreased. Hence correct option is C.

A man cannot see clearly the objects beyond a distance of 20 cm from his eyes. To see distant objects clearly the kind of lenses and its focal length must be 

structure of human eye human eye and colourful world

  1. 100 cm convex

  2. 100 cm concave

  3. 20 cm convex

  4. 20 cm concave

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Correct Option: D
Explanation:

$u= +20cm$

$v= \infty $

$\dfrac{1}{v}-\dfrac{1}{u}= \dfrac{1}{f}$

$\dfrac{1}{\infty }-\dfrac{1}{+20}= \dfrac{1}{f}$

$f=-20\ cm$

The power of a lens used to remove the myopic defect of an eye is 0.66 D. The far point for this eye is (nearly) :

structure of human eye human eye and colourful world

  1. 25 cm

  2. 150 cm

  3. 100 cm

  4. 75 cm

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Correct Option: B
Explanation:

As $p= \dfrac{1}{f}$


So, $f= \dfrac{1}{p}$

$\Longrightarrow$  $f= \dfrac{100}{0.66}cm$

$\Longrightarrow$ $f= 151.51cm$

$\Longrightarrow$ $f\simeq 150cm$

A myopic person can not see objects lying beyond 2m. The focal length and power of the lens required to remove this defect will be 

structure of human eye human eye and colourful world

  1. 1m and 0.5D

  2. -2m and -0.5D

  3. 0.5m and 0.5D

  4. -0.5, and 0.5D

Show answer
Correct Option: B
Explanation:

$u=+2m$

$v= \infty $

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

$\dfrac{1}{\infty }-\dfrac{1}{2}=\dfrac{1}{f}$

$f= -2m$

$P= \dfrac{1}{f}$

$= \dfrac{1}{-2}$

$= -0.5 D$

A long sighted person has a least distance of distinct vision of 50 cm. He wants to reduce it to 25 cm. He should use a :

structure of human eye human eye and colourful world

  1. Concave lens of focal length 50 cm

  2. Convex of focal length 25 cm

  3. Convex lens of focal length 50 cm

  4. Concave lens of focal length 25 cm

Show answer
Correct Option: C
Explanation:

Given, $u= \infty $


Image distance, $v= 50cm$

From lens formula, $\dfrac{1}{v}-\dfrac{1}{u}= \dfrac{1}{f}$

$\dfrac{1}{50}-\dfrac{1}{\infty }= \dfrac{1}{f}$

$f= +50\ cm$

He should use a convex lens of focal length 50 cm.

A person can see clearly objects lying between 25 cm and 2 m from his eye. His vision can be corrected by using spectacles of power:

structure of human eye human eye and colourful world

  1. +0.25 D

  2. +0.5 D

  3. -0.25 D

  4. -0.5 D

Show answer
Correct Option: D
Explanation:

Here, $u= 2m$
$v= \infty $

$\dfrac{1}{v}-\dfrac{1}{u}= \dfrac{1}{f}$

$\dfrac{1}{\infty}-\dfrac{1}{2}= \dfrac{1}{f}$

           $f= -2m$

Now, $P= \dfrac{1}{f}$

              $= \dfrac{1}{-2}D$

              $= -0.5\ D$

The power of lens, a short sighted person uses is 2 dioptre. The maximum distance of an object which he can see without spectacles is 

structure of human eye human eye and colourful world

  1. 25cm

  2. 50cm

  3. 100cm

  4. 10cm

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Correct Option: B
Explanation:

$f= \dfrac{1}{p}$

$= \dfrac{100}{2}cm$

$= 50\ cm$

So he can see upto a distance of 50 cm.

A person wears glasses of power 2D. The defect of the eye and the far point of the person without the glasses will be 

structure of human eye human eye and colourful world

  1. Nearsighted, 50 cm

  2. Farsighted, 50cm

  3. Nearsighted, 250 cm

  4. Astigmatism, 50 m

Show answer
Correct Option: B
Explanation:

$f= \dfrac{1}{p}$

  $=\dfrac{100}{2}cm$

  $=50\ cm$

The defect of eye will be farsighted.

The far point of a myopic eye is 250 cm. The correcting lens should be a

structure of human eye human eye and colourful world

  1. diverging lens of focal length 250 cm

  2. converging lens of focal length 250 cm

  3. diverging lens of focal length 125 cm

  4. converging lens of focal length 125 cm

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Correct Option: A
Explanation:

$u = -\infty $ 

$ v = -250 cm$

$\dfrac{1}{v}-\dfrac{1}{u}= \dfrac{1}{f}$

$(-\dfrac{1}{\infty}-\dfrac{1}{250})= \dfrac{1}{f}$

$f= -250cm$

The correcting lens of focal length $250 cm$.

The power of accommodation for the normal eye is

structure of human eye human eye and colourful world

  1. 4 D

  2. 40 D

  3. 44 D

  4. 400 D

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Correct Option: A
Explanation:

Our normal vision length = 25 cm which is eye lens focal length focal length  $f = 0.25 m$

Power $P=\dfrac{1}{f}=\dfrac{1}{.25}=4D$