Tag: approximation of square roots

Questions Related to approximation of square roots

Find the least number which must be subtracted from each of the following numbers so as to get a perfect square Also find the square root of the perfect square so obtained 
$(i) 402, (ii) 1989, (iii) 3250, (iv) 825, (v) 4000$

  1. Least number which must be subtracted:$(i) 2, (ii) 22, (iii) 1, (iv) 21, (v) 52$

    Square root of the perfect square:
    $(i) 20, (ii) 34 ,(iii) 55, (iv) 26, (v) 67$

  2. Least number which must be subtracted:$(i) 2, (ii) 53, (iii) 1, (iv) 41, (v) 31$

    Square root of the perfect square:
    $(i) 20, (ii) 44, (iii) 57, (iv) 28, (v) 63$

  3. Least number which must be subtracted:$(i) 6, (ii) 22, (iii) 50, (iv) 31, (v) 40$

    Square root of the perfect square:
    $(i) 19, (ii) 41, (iii) 49 ,(iv) 27 ,(v) 65$

  4. Least number which must be subtracted:$(i) 8, (ii) 41, (iii) 12, (iv) 56, (v) 4$

    Square root of the perfect square:
    $(i) 19 ,(ii) 22, (iii) 37, (iv) 26, (v) 61$


Correct Option: B
Explanation:

For $402$

Nearest perfect square is $400$
$\sqrt{400}$ $=$ $20$
$402$ $-$ $400$ $=$ $2$
For $1989$
Nearest perfect square is $1936$

$\sqrt{1936}$ $=$ $44$
$1936$ $-$ $1989$ $=$ $53$

For $3250$
Nearest perfect square is $3249$

$\sqrt{3249}$ $=$ $57$
$3250$ $-$ $3249$ $=$ $1$
For $825$
Nearest perfect square is $784$
$\sqrt{784}$ $=$ $28$
$825$ $-$ $784$ $=$ $41$
For $4000$
Nearest perfect square is $3969$
$\sqrt{3969}$ $=$ $63$
$4000$ $-$ $3969$ $=$ $31$
From this, Option B is correct answer.

Mr. Hansraj wants to find the least number of boxes to be added to get a perfect square. He already has $7924$ boxes with him. How many more boxes are required?

  1. $819$

  2. $412$

  3. $419$

  4. $176$


Correct Option: D
Explanation:

Find square root by long division method.

$\therefore \sqrt {7924}$ = $89.01$

Hence, the perfect square number smaller than $7924$ is
$89^2 = 7921$
The next perfect square no. is $90^2 = 8100$

So, $8100 - 7924 = 176$
Therefore, the man needs $176$ more boxes in order to get a perfect square number.
So, option D is correct.

$\displaystyle \sqrt { 4.8\times { 10 }^{ 9 } } $ is closest in value to

  1. $2200$

  2. $70000$

  3. $220000$

  4. $7000000$

  5. $22000000$


Correct Option: B
Explanation:

$\displaystyle \sqrt { 4.8\times { 10 }^{ 9 } } $

$=\sqrt{48\times10^{8}}$$\simeq$$7\times10^{4}=70000$
$7^{2}$$=$$49$
Hence Option B is correct.

What is an approximate value of $\sqrt{9805}$?

  1. 98.56

  2. 97.23

  3. 99.05

  4. 100.34


Correct Option: C
Explanation:

$99^2$ = 9801
$100^2$ = 10000
In between this two squares, 9805 is placed.
So the average of $\frac{99 + 100}{2}= 99.5$
Then, $99.5^2 = 9900.25$
So, $\sqrt{9805} \approx 99.05$

Estimate the square root of 500.

  1. 22.5

  2. 20.3

  3. 21.4

  4. 23.6


Correct Option: A
Explanation:

$22^2$ = 484
$23^2$ = 576
In between this two square numbers, 500 is placed.
So average of $\frac{22 + 23}{2}= 22.5$
Then, $22.5^2 = 506.25$
So, $\sqrt{500} \approx 22.5$

Find the approximate value of $\sqrt{5245}$.

  1. 70.5

  2. 72.3

  3. 71.8

  4. 79.2


Correct Option: B
Explanation:

$72^2$ = 5184
$73^2$ = 5329
In between this two squares, 5245 is placed.
So average of $\frac{72 + 73}{2}= 72.5$
Then, $72.5^2 = 5256.25$
So, $\sqrt{5245} \approx 72.3$

Find the approximate value of $\sqrt{1235}$.

  1. $35.15$

  2. $32.19$

  3. $30.25$

  4. $29.13$


Correct Option: A
Explanation:

$35^2$ = 1225
$36^2$ = 1296
In between this two squares, 1235 is placed.
So the average of $\dfrac{35 + 36}{2}= 35.5$
Then, $35.5^2 = 1260.25$

So $\sqrt{1235}\approx35.15$

Estimate the value of $\sqrt{750}$.

  1. 24.3

  2. 25.1

  3. 23.2

  4. 27.3


Correct Option: D
Explanation:

$27^2$ = 729
$28^2$ = 784
In between this two squares, 750 is placed.
So average of $\frac{27 + 28}{2}= 27.5$
Then, $27.5^2 = 756.25$
So, $\sqrt{750} \approx 27.3$

Estimate the square root of $300$

  1. $12.44$

  2. $16.66$

  3. $17.32$

  4. $18.54$


Correct Option: C
Explanation:

The square root of $300$ is $10\sqrt 3$

We know that $\sqrt 3=1.732$
Thus $\sqrt{300}=10\times 1.732=17.32$

Estiamate the square root of $850$ 

  1. $29.15$

  2. $30.21$

  3. $98.23$

  4. $23.11$


Correct Option: A
Explanation:

The square root of $850$ is $\sqrt {850}=\sqrt {25 \times 34}=5\sqrt {34}$

Square root of $34$ lie between $5$ and $6$.
 square of $5.5$ is $30.25$ 
Now, we can say that square root of $34$ lie between $5.5$ and $6$.
Now, square of $5.75$ is $33.06$
So, square root of $34$ lie between $5.75$ and $6$.
Now, we have to choose the number $5.85$
$(5.85)^2=34.225$ which is greater than $34$ and close to $34$
So, assume a number $5.84$.
$(5.84)^2=34.1056$
$(5.83)^2=33.9889$
Hence, we can say that square root of 34 lie between $5.83$ and $5.84$.
So, $5\times 5.83=29.15$.