Tag: compatibility of blood groups

Questions Related to compatibility of blood groups

Biological marriage of one of the following should be avoided
                                                 or

After examining the blood groups of a couple, the doctor advised them not to have more than one child. The blood group of the couple are likely to be

                                                or

In which of the following situations, is there a risk factor for children of incurring erythroblastosis foetalis

  1. Rh+ male and Rh- female

  2. Rh+ male and Rh+ female

  3. Rh- male and Rh+ female

  4. Rh- male and Rh- female


Correct Option: A

The problem of erythroblastosis foetalis occurs when 

  1. Both father and mother are Rh positive

  2. Both father and mother are Rh negative

  3. Mother is Rh positive and father is Rh negative

  4. Father is Rh positive and mother is Rh negative


Correct Option: D
Explanation:

If a woman who is Rh- negative married to a man who is Rh- positive produces a baby may have Rh- positive blood, inherited from the father. Rh antibodies are harmless until the mother's second or later pregnancies. If she is ever carrying another Rh- positive child, her Rh antibodies will recognize the Rh proteins on the surface of the baby's blood cells as foreign and attack those cells. This can lead to rupture of the baby's RBCs known as haemolytic or Rh disease of the newborn or erythroblastosis foetalis. 

Therefore, the correct answer is option D.

Name of the disease due to Rh factor.

  1. Accquired Immuno Deficiency Syndrome

  2. Turner's Syndrome

  3. Erythroblastosis foetalis

  4. Sickle - cell anaemia


Correct Option: C
Explanation:

When a woman is pregnant having Rh negative blood group and the blood group of the foetus is Rh positive, then her baby's blood type will be incompatible with her own. This can cause a condition known as erythroblastosis fetalis, where the mother's red blood cells attack those of the baby as there would any foreign invaders. Rh incompatibility and ABO incompatibility are the two main cause. Both are associated with blood type. Thus, the correct answer is option C.

A doctor suggested to a couple not to have more than one child because of

  1. $Rh^+$ male and $Rh^-$ female

  2. $Rh^-$ male and $Rh^+$ female

  3. $Rh^+$ male and $Rh^+$ female

  4. $Rh^-$ male and $Rh^-$ female.


Correct Option: A

Chances of erythroblastosis foetalis occurring during second pregnancy when the baby is

  1. $Rh^+$ and mother $Rh^-$

  2. $Rh^+$ and mother $Rh^+$

  3. $Rh^-$ and mother is $Rh^+$

  4. $Rh^-$ and mother $Rh^-$.


Correct Option: A

If a women becomes pregnant second time, the foetus is in danger when

  1. Mother is Rh (+) ve and foetus is Rh (-) ve

  2. Mother is Rh (-) ve and foetus is Rh (+) ve

  3. Father is Rh (-) ve and foetus is Rh (+) ve

  4. Father is Rh (+) ve and foetus is Rh (-) ve.


Correct Option: B

The problem due to Rh factor arises when the two blood (Rh${^+}$ and Rh${^-}$ ) mix up

  1. In a test tube

  2. Through transfusion

  3. During pregnancy

  4. All of the above


Correct Option: D
Explanation:

Rh incompatibility arises when mother and the baby carries different protein factors. The problem arises when mother is Rh negative and the child she is carrying is Rh positive. This can take place even when two blood groups with different proteins are either mixed in a test tube or transfused into a person. Rh negative people do not have this protein and if Rh positive blood is mixed with Rh negative blood anti Rh antibodies develop which can lead to problems. 

In erythroblastosis foetalis, which factors of the mother pass through placenta into the fetus?

  1. Rh antigens

  2. Rh antibodies

  3. ABO antibodies

  4. Agglutinins


Correct Option: B
Explanation:

Erythroblastosis fetalis also called the hemolytic disease of the newborn, type of anemia in which the red blood cells (erythrocytes) of a fetus are destroyed in a maternal immune reaction resulting from a blood group incompatibility between the fetus and its mother. Symptoms of erythroblastosis fetalis range from mild to severe; death of the fetus or newborn sometimes results.

The Rh system is responsible for the most severe form of the disease, which can occur when a Rh-negative woman (a woman whose blood cells lack the Rh factor) conceives a Rh-positive fetus. Sensitization of the mother’s immune system (immunization) occurs when fetal red blood cells that carry the Rh factor (an antigen in this context) cross the placental barrier and enter the mother’s bloodstream. They stimulate the production of antibodies, some of which pass across the placenta into fetal circulation and lyse, or break apart, the red blood cells of the fetus (hemolysis). Hence option B is correct.

Erythroblastosis foetalis is caused when fertilisation takes place between gametes of

  1. $Rh^-$ female and $Rh^+$ male.

  2. $Rh^+$ female and $Rh^-$ male.

  3. $Rh^+$ female and $Rh^+$ male.

  4. $Rh^-$ female and $Rh^-$ male.


Correct Option: A
Explanation:
 Erythroblastosis foetalis is caused by transplacental transmission of maternal antibodies to foetal RBCs when  mother is Rh- and the foetus is Rh+.
So, the correct option is 'Rh- female and Rh+ male'

In which of the following situations, there is a risk factor for children acquiring erythroblastosis foetalis?

  1. Mother is Rh -ve and father is Rh -ve.

  2. Mother is Rh -ve and father is Rh +ve.

  3. Mother is Rh +ve and father is Rh +ve.

  4. Mother is Rh +ve and father is Rh -ve.


Correct Option: B
Explanation:
Erythroblastosis fetalis also called hemolytic disease of the newborn, type of anemia in which the red blood cells (erythrocytes) of a fetus are destroyed in a maternal immune reaction resulting from a blood group incompatibility between the fetus and its mother. This happens during second pregnancy when the mother's immune system is already sensitized to Rh$^+$ antigens present on the blood cells of the foetus during the first pregnancy. The Rh gene being dominant, the feotus will be Rh$^+$ if anyone of the parent is Rh$^+$.
 So, the correct answer is "Mother is Rh-ve and father is Rh+ve."