Tag: scalars and vectors
Questions Related to scalars and vectors
The distance of the point (1,3) from the line 2x-3y+9=0 measured along a line x-y+1=0 is
If $L _1$ is the line of intersection of the plane $2x-2y+3z-2=0, x-y+z+1=0$ and $L _2$ is the line of intersection of the plane $x+2y-z-3=0, 3x-y+2z-1=0$, then the distance of origin from from the plane containing the lines $L _1$ + $L _2$ is :
The equation of plane which is passing through the point $(1,2,3)$ and which is at maximum distance from the point $(-1,0,2)$ is
The distance of the point $P(3,8,2)$ from the line $\dfrac{x-1}{2}=\dfrac{y-3}{4}=\dfrac{z-2}{3}$ measured parallel to the plane $3x+2y-2z+15=0$ is
If the shortest distance between the line
$\dfrac {x-1}{\alpha}=\dfrac {y+1}{-1}=\dfrac {z}{1}(\alpha \neq 1)$ and $x+y+z+1=0=2x-y+z+3$ is $\dfrac {1}{\sqrt {3}}$, then a value $\alpha$ is:
The shortest distance between line $y-x=1$ and curve $x=y^{2}$ is :-
A point $Q$ at a distance $3$ from the point $P(1,1,1)$ lying on the line joining the points $A(0,-1,3)$ and $P$, has the coordinates
The distance of the point $\left( 1,-2,3 \right) $ from the plane $x-y+z=5$ measured parallel to the line $\displaystyle \frac { x }{ 2 } =\frac { y }{ 3 } =\frac { z-1 }{ -6 } $ is
The points $(4, -5, 1)$, $(3, -4, 0)$, $(6, -7, 3)$, $(7, -8, 4)$ are vertices of a
$A, B, C$ are three points on the axes of $x, y$ and $z$ respectively at distance $a, b, c$ from the origin $O$; then the co - ordinates of the point which is equidistant from $A, B, C$ and $O$ is