Tag: study of diborane

Questions Related to study of diborane

Which of the following statement about boron carbide is wrong?

  1. Its molecular formula is $B _4C$.

  2. It is also called Norbia.

  3. It is the hardest substance.

  4. It is used for cutting glasses.


Correct Option: C
Explanation:

Boron carbide $B _4C$ is an extremely hard boroncarbon ceramic material used in tank armor, bulletproof vests, engine sabotage powders and  is called Norbia.

In the arts, silicon carbide is a popular abrasive in modern lapidary due to the durability and low cost of the material. In manufacturing, it is used for its hardness in abrasive machining processes such as grinding, honing, water-jet cutting and sandblasting. 

Particles of silicon carbide are laminated to paper to create sandpapers and the grip tape on skateboards.

Find the incorrect match.

  1. $Al _2Cl _6$ : $3C - 4e$ bond is present

  2. $Al _2(CH _3) _6$ : All carbon atoms are $sp^{3}$ - hybridized

  3. $I _2Cl _6$ : Nonplanar

  4. $Al _2Br _6$ : Nonpolar


Correct Option: C
Explanation:

A) $Al _2Cl _6$ contains, $3C-4e$ bonds. In each such bond, two $Al$ atoms and one $Cl$ atom participate. Each $Al$ atom contributes $1$ electron and $Cl$ atom contributes $2$ electrons. Thus, the option A is correct.
B) In $Al _2(CH _3) _6$, all $C$ atoms are $sp^3$ hybridized and result in tetrahedral geometry. Thus, the option B is correct.
C) In $I _2Cl _6$, each iodine atom is $sp^3d^2$ hybridized with $4$ bond pairs and two lone pairs. Each iodine atom has square planar geometry. The repulsion between the lone pair of electrons on two iodine atoms will be minimized when the molecule is planar. Thus, the option C is incorrect.
D) $Al _2Br _6$ molecule is non planar as each $Al$ atom is $sp^3$ hybridized. Thus, the option D is correct.

Find out the similarities between $I _2Cl _6$ and $Al _2Cl _6$.

  1. Both have $3C\, -\, 4e^-$ bond

  2. Both have $sp^3$- hybridization for the central atom

  3. Both are nonplanar

  4. All are correct


Correct Option: A
Explanation:

A)  Both $ I _2Cl _6$ and $ Al _2Cl _6$ have $ 3C\, -\, 4e^-$ bonds. Hence, option A is correct.
B) In $ I _2Cl _6$, the central $I$ atom undergoes $sp^3d^2$ hybridization and in $ Al _2Cl _6$, the central $Al$ atom undergoes $sp^3$ hybridization. Thus, the option B is incorrect.
C) $ I _2Cl _6$ is planar and $ Al _2Cl _6$ is non planar. Thus, the option C is incorrect.

Which of the following molecule has $3C\, -\, 4e^-$ bond?

  1. $Al _2Cl _6$

  2. $Be _2Cl _4$

  3. $I _2Cl _6$

  4. All are having $3C\, -\, 4e^-$ bond


Correct Option: D
Explanation:

 $3C-4e^-$ bond is a model used to explain bonding in certain hypervalent molecules such as tetratomic & hexatomic interhalogen compounds, sulphur tetrafluoride, xenon fluoride and the fluoride ions.

$Al _2Cl _6$, $Be _2Cl _4$ and $I _2Cl _6$ contain $3C\, -\, 4e^-$ bond. The chlorine atoms acts as bridges and forms one covalent bond and other coordinate bond.

Which one of the following methyl diboranes does not exist?

  1. $B _2H _4(CH _3) _2$

  2. $B _2H _3(CH _3) _3$

  3. $B _2H _2(CH _3) _4$

  4. $B _2H(CH _3) _5$


Correct Option: D
Explanation:

Di borane forms methyl diborane($B _2H _5(CH _3))$,dimethyl diborane($B _2H _4(CH _3) _2$),trimethyl diborane($B _2H _3(CH _3) _3$) ,tetramethyl diborane($B _2H _2(CH _3) _4$).

So $B _2H(CH _3) _5$ can not form,becuase in this compound we have to use bridge hydrogen for the formation of this compound,that never happens.

Hence option D is correct.

Identify the statement(s) that is/are correct as far as structure of diborane is concerned :

  1. There are two bridging hydrogen atoms in diborane.

  2. Each boron atom forms four bonds in diborane.

  3. The hydrogen atoms are not in the same plane in diborane.

  4. All B-H bonds in diborane are similar.


Correct Option: A,B,C

Which of the following overlapping is used for the formation of $3C\, -\, 2e^-$ bond in chain polymer of $BeMe _2$ ?

  1. $sp\, -\, sp\, -\, sp$

  2. $sp^2\, -\, sp^2\,-\, sp^2$

  3. $sp^2\, -\, sp^3\, -\, sp^2$

  4. $sp^3\, -\, sp^3\, -\, sp^3$


Correct Option: D
Explanation:

$sp^3\, -\, sp^3\, -\, sp^3$ overlapping is used for the formation of $3C\, -\, 2e^-$ bond in chain polymer of $BeMe _2$. Thus, the $Be$ atom and $C$ atom of each methyl group is $sp^3$ hybridized.

Which type of bond is present in $[BeF _2] _n$ polymer?

  1. $3C-2e^-$

  2. $3C-4e^-$

  3. $3C-3e^-$

  4. None of these


Correct Option: B
Explanation:

$[BeF _2] _n$ contains $3C-4e^-$ bonds.
One $F$ atom and two $Be$ atoms are $3$ centers. The middle $O$ contributes two electrons each to the be atom, thereby a total of $4$ electrons are contributed and it forms $BeFBe$ bridges. 

Which is/are correct representation of boranes?

  1. $B _n\, H _{n\, +\, 4}$

  2. $B _n\, H _{n\, +\, 6}$

  3. $B _n\, H _{2n\, +\, 2}$

  4. None of these


Correct Option: A,B
Explanation:

The correct representation of boranes include (A) $B _n\, H _{n\, +\, 4}$, called as nido-boranes and (B) $B _n\, H _{n\, +\, 6}$, called as arachno boranes.
(C) $B _n\, H _{2n\, +\, 2}$ is not a correct representation of boranes.
Note: $B _n\, H _{n\, +\, 6}$ are less stable than $B _n\, H _{n\, +\, 4}$

Select the correct statements(s).

  1. $BeCl _2$ tends to dimerize to a 3-coordinate structure in vapor phase, but linear monomer is also known at high temperature.

  2. $BeF _2$ has $3C - 4e^-$ bond.

  3. Bond lengths in all the boron trihalides are shorter than expected for single bonds.

  4. $BeF _2$ is analogous to $CO _2$ and $BF _3$ analogous to $SO _3$


Correct Option: A,C,D
Explanation:

(B) $BeF _2$ has $3C - 2e^-$ bond.

The correct statements are: 
(A) $BeCl _2$ tends to dimerize to a 3-coordinate structure in vapor phase which involves chlorine bridges, but linear monomer is also known at high temperature.
(C) Bond lengths in all the boron trihalides are shorter than expected for single bonds. This indicates presence of multiple bonds.
(D) $BeF _2$ is analogous to $CO _2$ as both have linear geometry. $BF _3$ analogous to $SO _3$ as both have plane triangular geometry.