Tag: other quantities

Questions Related to other quantities

The ratio of $\left(\displaystyle\dfrac{1}{3}\text{ of Rs. }9.30\right)$ to $(0.6\text{ of Rs. }1.55)$ is ___________.

maths ratio, proportion and unitary method converting to ratios finding ratios other quantities

  1. $1:3$

  2. $10:3$

  3. $3:10$

  4. $3:1$

Show answer
Correct Option: B
Explanation:

$\displaystyle\frac{1}{3}$ of Rs. $9.30=Rs. \left(\displaystyle\frac{1}{3}\times 9.30\right)=Rs. 3.10$
$0.6$ of Rs. $1.55=$Rs. $(0.6\times 1.55)=$ Rs. $0.93$
$\therefore$ Required ratio$=3.10:0.93=10:3$.

Cost of a candy is $50$ paise and cost of an ice cream is Rs. $20$, then the ratio of the cost of a candy to the cost of an ice-cream is __________.

maths ratio, proportion and unitary method converting to ratios finding ratios other quantities

  1. $40:1$

  2. $1:40$

  3. $1:20$

  4. $1:15$

Show answer
Correct Option: B
Explanation:

Cost of $1$ candy $=50$ paise
Cost of $1$ ice-cream $=Rs. 20=20\times 100$ paise
$=2000$ paise
$\therefore$ Required ratio $=50:2000=1:40$.

Out of $30$ students in a class, $6$ like football, $12$ like cricket and remaining like tennis. The ratio of number of students who like tennis to the total number of students, is:

maths ratio, proportion and unitary method converting to ratios finding ratios other quantities

  1. $2:3$

  2. $5:1$

  3. $2:5$

  4. $5:2$

Show answer
Correct Option: C
Explanation:
Total number of students$=30$
Number of students who like football$=6$
Number of students who like cricket$=12$
$\therefore$ Number of students who like tennis $=30-6-12=12$
$\therefore$ Required ratio $=12:30=2:5$.