Tag: blood group

Questions Related to blood group

The problem due to Rh factor arises when the two blood (Rh${^+}$ and Rh${^-}$ ) mix up

  1. In a test tube

  2. Through transfusion

  3. During pregnancy

  4. All of the above


Correct Option: D
Explanation:

Rh incompatibility arises when mother and the baby carries different protein factors. The problem arises when mother is Rh negative and the child she is carrying is Rh positive. This can take place even when two blood groups with different proteins are either mixed in a test tube or transfused into a person. Rh negative people do not have this protein and if Rh positive blood is mixed with Rh negative blood anti Rh antibodies develop which can lead to problems. 

In erythroblastosis foetalis, which factors of the mother pass through placenta into the fetus?

  1. Rh antigens

  2. Rh antibodies

  3. ABO antibodies

  4. Agglutinins


Correct Option: B
Explanation:

Erythroblastosis fetalis also called the hemolytic disease of the newborn, type of anemia in which the red blood cells (erythrocytes) of a fetus are destroyed in a maternal immune reaction resulting from a blood group incompatibility between the fetus and its mother. Symptoms of erythroblastosis fetalis range from mild to severe; death of the fetus or newborn sometimes results.

The Rh system is responsible for the most severe form of the disease, which can occur when a Rh-negative woman (a woman whose blood cells lack the Rh factor) conceives a Rh-positive fetus. Sensitization of the mother’s immune system (immunization) occurs when fetal red blood cells that carry the Rh factor (an antigen in this context) cross the placental barrier and enter the mother’s bloodstream. They stimulate the production of antibodies, some of which pass across the placenta into fetal circulation and lyse, or break apart, the red blood cells of the fetus (hemolysis). Hence option B is correct.

Erythroblastosis foetalis is caused when fertilisation takes place between gametes of

  1. $Rh^-$ female and $Rh^+$ male.

  2. $Rh^+$ female and $Rh^-$ male.

  3. $Rh^+$ female and $Rh^+$ male.

  4. $Rh^-$ female and $Rh^-$ male.


Correct Option: A
Explanation:
 Erythroblastosis foetalis is caused by transplacental transmission of maternal antibodies to foetal RBCs when  mother is Rh- and the foetus is Rh+.
So, the correct option is 'Rh- female and Rh+ male'

In which of the following situations, there is a risk factor for children acquiring erythroblastosis foetalis?

  1. Mother is Rh -ve and father is Rh -ve.

  2. Mother is Rh -ve and father is Rh +ve.

  3. Mother is Rh +ve and father is Rh +ve.

  4. Mother is Rh +ve and father is Rh -ve.


Correct Option: B
Explanation:
Erythroblastosis fetalis also called hemolytic disease of the newborn, type of anemia in which the red blood cells (erythrocytes) of a fetus are destroyed in a maternal immune reaction resulting from a blood group incompatibility between the fetus and its mother. This happens during second pregnancy when the mother's immune system is already sensitized to Rh$^+$ antigens present on the blood cells of the foetus during the first pregnancy. The Rh gene being dominant, the feotus will be Rh$^+$ if anyone of the parent is Rh$^+$.
 So, the correct answer is "Mother is Rh-ve and father is Rh+ve."

In which of the following situations, is there a risk factor for children of incurring erythroblastosis foetalis?

  1. Mother is Rh -ve and father is Rh -ve.

  2. Mother is Rh -ve and father is Rh +ve.

  3. Mother is Rh +ve and father is Rh +ve.

  4. Mother is Rh +ve and father is Rh -ve.


Correct Option: B
Explanation:

There are two main causes of erythroblastosis fetalis: Rh incompatibility and ABO incompatibility. Rh incompatibility occurs when a Rh-negative mother is impregnated by a Rh-positive father. The result can be a Rh-positive baby. In such a case, your baby’s Rh antigens will be perceived as foreign invaders, the way viruses or bacteria are perceived. Your blood cells attack the baby’s as a protective mechanism that can end up harming the child. If you’re pregnant with your first baby, Rh incompatibility isn’t as much of a concern. However, when the Rh-positive child is born, your body will create antibodies against the Rh factor. These antibodies will attack the blood cells if you ever become pregnant with another Rh-positive baby.


So, the correct option is 'Option B'.

Rh factor may be responsible for

  1. Turner's syndrome

  2. Accquired Immuno Deficiency Syndrome

  3. Sickle cell anaemia

  4. Erythroblastosis foetalis


Correct Option: D
Explanation:

Erythroblastosis foetalis is a disease of the new born which is caused by Rh incompatibilty. This happens when mother is Rh negative and the child she is bearing is Rh positive. Thus the Rh antigen of child can trigger the antibodies inside mother which can travel through circulation thus destroying foetus blood cells. Thus, correct answer is option D.

Several copies of genes carrying the contrasting characters are mainly included in which of the following laws?

  1. Law of independent assortment

  2. Law of segregation

  3. Multiple allelism

  4. None of the above


Correct Option: C
Explanation:
Alleles are alternative forms of a gene. They are responsible for differences in phenotypic expression of a given trait. When a gene exists in three or more allelic forms it is called multiple allele. 
For example, ABO blood group system in humans is controlled by three alleles  I$^A$, I$^B$, and  I$^O$
IA and IB are codominant and make type A and type B antigens, respectively. IO is the recessive allele and produces no antigen.The blood groups arising from the different possible genotypes is given below.
Genotype                         Blood Group
I$^A$ I$^A$                        A
I$^A$ I$^O$                       A
I$^B$ I$^B$                        B
I$^B$ I$^O$                       B
I$^A$ I$^B$                      AB
I$^O$ I$^O$                      O
So, the correct answer is 'Multiple allelism'

Multiple alleles are situated at 

  1. Homologous chromosme at same locus

  2. Homologous chromosome at different locus

  3. Non-homologous chromosome at different locus

  4. None of the above


Correct Option: A
Explanation:

Alleles are alternative forms of a gene. They are responsible for differences in phenotypic expression of a given trait. When a gene exists in three or more allelic forms it is called multiple allele. Homologous chromosomes are chromosome pairs, one from each parent. They are similar in length, gene position and centromere location. Multiple alleles are situated in homologous chromosome at the same locus. Thus the correct answer is option A.

If both parents are albino, all the offspring shall be

  1. Albino

  2. Some albino, some normal

  3. Homozygous normal

  4. Heterozygous normal


Correct Option: A
Explanation:

Albinism is a autosomal genetical recessive gene disorder. It occurs in homozygous recessive state. The gene for albinism is a. it does not produce the enzyme tyrosinase, but is normal Allele A is does. Thus only homozygous individuals (aa) is affected. When both parents are albinic, all the offsprings also albinic generally.

So, the correct option is ‘Albino’.

When the heterozygote in a population have a reproductive advantage, one can predict that _________________.

  1. They will produce only heterozygous offspring

  2. The individuals that are homozygous recessive will take over

  3. Both homozygous dominant and homozygous recessive individuals will continue to appear in future generations

  4. Homozygous dominant and homozygous recessive individuals will be completely eliminated


Correct Option: A