"A six digit number 312132 has two 1's, two 2's and two 3's. This number has a very interesting attribute: 1 digit exists between two 1s, 2 digits exist between two 2's and 3 digits exist between two 3s. Can we add two more 4s to become an eight digit number and still holding the above attributes plus 4 digits exist between two 4s? "

general knowledge math & puzzles

  1. 12341234 or 23421314

  2. 12341234 or 23412341

  3. 41312432 or 23421314

  4. 34211234 or 23412341

Show answer
Correct Option: C
Explanation:

To solve this question, the user needs to understand the pattern of the given six-digit number and apply it to find the correct eight-digit number that satisfies all the given conditions.

The given six-digit number is 312132, which has two 1s, two 2s, and two 3s, with 1 digit between two 1s, 2 digits between two 2s, and 3 digits between two 3s.

We need to add two more 4s to the number and still keep the pattern. We know that four digits should exist between two 4s. Therefore, we can place the first 4 between the two 1s, and the second 4 between the two 2s, resulting in an eight-digit number.

Let's go through each option to find the one that satisfies all the given conditions:

A. 12341234 or 23421314: These options do not satisfy the condition that 4 digits should exist between two 4s.

B. 12341234 or 23412341: These options do not satisfy the condition that 3 digits should exist between two 3s.

C. 41312432 or 23421314: The option 23421314 satisfies all the given conditions, with two 1s, two 2s, two 3s, and two 4s, with 1 digit between two 1s, 2 digits between two 2s, 3 digits between two 3s, and 4 digits between two 4s.

D. 34211234 or 23412341: These options do not satisfy the condition that 2 digits should exist between two 2s.

Therefore, the correct answer is:

The Answer is: C. 41312432 or 23421314.

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