Tag: work and energy

Questions Related to work and energy

The number of joules contained in 1kWh is_____

  1. $36 \times 10^2$

  2. $36 \times 10^3$

  3. $36 \times 10^4$

  4. $3.6 \times 10^6$


Correct Option: D
Explanation:

The kilowatt hour is a unit of energy equal to 3.6 megajoules. If the energy is being transmitted or used at a constant rate over a period of time, the total energy in kilowatt hours is the power in kilowatts multiplied by the time in hours.

Let energy is used as 1J/s. For an hour or 3600 sec. Then total energy used is 3600J. And kWh means 1000$\times$3600.
Which gives $3.6\times10^6$.

$ kg  m^2 s^{-2}$ represents the unit of_____

  1. kinetic energy

  2. work done

  3. potential energy

  4. all the above


Correct Option: D
Explanation:

the given unit $kgm^2s^{-2}$ is unit of energy and  any of the energy either potential or kinetic will have  same unit 

also work done is given by $F.S$ or $kgms^{-2}.m$ or $kgm^2s^{-2}$
so the unit of work is also same.
so the given unit represent unit for all the three quantities in the options.

Work required to produce $1000   k$ - calorie heat will be

  1. $4.2 Joule$

  2. $0.42 \times {10}^{6} Joule$

  3. $4.2 \times {10}^{6} Joule$

  4. $4.2 \times {10}^{7} Joule$


Correct Option: C
Explanation:

In this problem, we have to convert the heat energy in unit from calorie to Joule. 

According to work-energy theorem, the work is also a energy. 
Thus, $1000k.cal=1000\times 10^3 cal=10^6 cal=4.2\times 10^6 J$  (as $1 cal=4.2 J$)

$1Wh=$

  1. $36kJ$

  2. $3.6kJ$

  3. $3600kJ$

  4. $3.6MJ$


Correct Option: B
Explanation:

$1Wh=1W\times{1h}$

$=1{J}.{s}^{-1}\times{3600}s$

$=3600J=3.6kJ$

Kilowatt-hour is the unit of

  1. potential difference

  2. electric power

  3. electrical energy

  4. charge


Correct Option: C
Explanation:

Electrical energy $V \times l \times t$
Electric energy unit $= kW  hour$

$1kWh=$

  1. $3.6J$

  2. $3.6kJ$

  3. $3.6MJ$

  4. $3.6GJ$


Correct Option: C
Explanation:

$1kWh=1kW\times{1h}$

$=1000{J}.{s}^{-1}\times{3600}s$

$=3.6\times{10}^{6}J=3.6MJ$

A window whose area is $2m^2$ opens on street where the street noise result in an intensity level at the window of $60db$. How much acoustic power enters the window via sound waves ? Now, if an acoustic absorber is fitted at the window? 

  1. $8\mu W$

  2. $10\mu W$

  3. $4\mu W$

  4. $2\mu W$


Correct Option: D
Explanation:

Intensity = 60 dB

60 = 10 log $(\frac{I}{I _{ref}})$

where $I _{ref}$ is the refrence intensity , general value of this is given by 

$I _{ref} = 10^{-12}\frac{watt}{m^2}$

$\frac{I}{10^{-12}}$ = anti log (6)

$I = 10^{-12}  \times{anti log(6)} = 10^{-12} \times{10^6} = 10^{-6}$

Power = I$\times$ area = $2 \times{10^{-6}}$ watt

The internal energy change when a system goes from state A to B is $40$ kJ/mole. If the system goes from A to B by a reversible path and returns to state A by an irreversible path what would be the net change in internal energy?

  1. $40$ kJ

  2. $> 40$ kJ

  3. $< 40$ kJ

  4. Zero


Correct Option: D
Explanation:
For a cyclic process the net change in the internal energy is zero because the change in internal energy doesnot depend on the path.

Which of the following can be negative 

  1. Kinetic energy

  2. Potential energy

  3. Mechanical energy

  4. All of these


Correct Option: B,C
Explanation:

Mechanical energy & potential energy can be negative.

$\therefore$ Option $B$ and $C$.

If the unit of force and length be each increased by four times, then the unit of energy is increased by

  1. 16 times

  2. 8 times

  3. 2 times

  4. 4 times


Correct Option: A
Explanation:

Unit of Energy = Unit of Force $\times$ Unit of length 
So if we increase unit of length and force, each by four times, then unit of energy will increase by sixteen times.