Tag: nitrogen and sulfur

Questions Related to nitrogen and sulfur

When Ammonical common salt solution is saturated with carbon dioxide we obtain ?

  1. $NH _4HCO _3$

  2. $(NH _4) _2CO _3$

  3. $NaHCO _3$

  4. $Na _2CO _3$


Correct Option: C
Explanation:

Ammonical solution of common salt.

$CO _2+NH _3+NaCl+H _2O\longrightarrow NaHCO _3+NH _4Cl$
$\therefore$ By treating $CO _2$ with ammonical $NaCl$ we get sodium bicarbonate $(NaHCO _3)$ and ammonium sulphate.
Answer is option C.

Chlorine reacts with excess of ammonia to form:

  1. ${ NH } _{ 4 }Cl$

  2. ${ N } _{ 2 }+HCl$

  3. ${ N } _{ 2 }+{ NH } _{ 4 }Cl$

  4. ${ N } _{ 2 }+{ HCl} _{ 3 }$


Correct Option: C
Explanation:

Pure chlorine gas may react vigorously with ammonia gas. An excessive mix of the two gases in the air can produce hazardous compounds such as the explosive nitrogen trichloride. In facilities that use chloramination, the pure chlorine and ammonia need to be stored in separate, sealed rooms or buildings.

When ammonia is excess,

$3 Cl _2 + 8 NH _3 \rightarrow 6 NH _4Cl + N _2 (g)$

The formal charge on nitrogen atom in ammonium ion is 

  1. $3$

  2. $2$

  3. $1$

  4. $4$


Correct Option: A

Ammonia, $NH _3$ and hydrazine, $NH _2NH _2$, are two compounds of nitrogen, $N _2$. Which statement is correct?

  1. The N-N bond in $NH _2NH _2$ is polar

  2. $NH _3$ and $NH _2NH _2$ have lone pairs of electrons but $N _2$ does not

  3. The oxidation number of each nitrogen in $NH _2NH _2$ is $+2$

  4. The reaction of nitrogen with hydrogen has a high activation energy


Correct Option: D
Explanation:

Solution:- (D) The reaction of nitrogen with hydrogen has high activation energy.


The $N-N$ bond in $N{H} _{2} N{H} _{2}$ is a non-polar bond because $N$ and $N$ have the same electronegativity value.

${N} _{2}$ also has a lone pair of electron on each nitrogen atom.

The oxidation number of each hydrogen in $N{H} _{2}N{H} _{2}$ is $+1$, thus the oxidation number of each nitrogen in $N{H} _{2}N{H} _{2}$ is $-2$.

Due to high bond energy, the reaction of nitrogen with hydrogen has high activation energy.

Hence statement $\left( D \right)$ is correct.

$NaOCl$ reacts with $NH _3$ to produce :

  1. $NH _2OH$

  2. $NH _2NH _2$

  3. $N _2$

  4. $NO$


Correct Option: B
Explanation:

Reaction:

$NaOCl + NH _3 \rightarrow NH _2Cl + NaOH$
$NH _2Cl + NH _3 + NaOH \rightarrow N _2H _4 + NaCl + H _2O$.

Name a gas whose solution in water is alkaline.

  1. Ammonia

  2. Chlorine

  3. $SO _2$

  4. $HCl$


Correct Option: A
Explanation:

Ammonia readily dissolves in water with the liberation of heat. These aqueous solutions of ammonia are basic and are called ammonium hydroxide.
$ { NH } _{ 3 }+{ H } _{ 2 }O\rightleftharpoons { { NH } _{ 4 } }^{ + }+OH^{ - }$

Which of the following gas burns in oxygen with a green flame?

  1. Ammonia

  2. Hydrogen chloride

  3. Sulphur dioxide

  4. Hydrogen sulphide


Correct Option: A
Explanation:

On combustion, ammonia gas burns with pale yellowish green flame.

What are the products formed when ammonia is oxidized with copper oxide?

  1. ${ N } _{ 2 }$

  2. ${ H } _{ 2 }O$

  3. $Cu$

  4. All of the above


Correct Option: D
Explanation:

${ 2NH } _{ 3 }+3CuO\rightarrow { N } _{ 2 }+{ 3H } _{ 2 }O+3Cu$

Gases: ammonia, chlorine, hydrogen chloride and sulphur dioxide 

Select the gas that matches the description given.

Statement : The gas turns moist red litmus paper blue.

  1. Chlorine

  2. Ammonia

  3. Sulphur dioxide

  4. Hydrogen chloride


Correct Option: B
Explanation:

Ammonia is basic in nature which turns red litmus paper to blue and confirms that ammonia is alkaline gas.

Formation of ammonium sulphate from ammonia and dil sulphuric acid is given by :

  1. ${3NH } _{ 3 }+{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { \left(2 { NH } _{ 4 } \right) } _{ 2 }{ SO } _{ 4 }$

  2. ${ 2NH } _{ 3 }+{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { \left( { NH } _{ 4 } \right) } _{ 2 }{ SO } _{ 4 }$

  3. ${ 2NH } _{ 3 }+3{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { \left( { NH } _{ 4 } \right) } _{ 2 }{ SO } _{ 4 }$

  4. ${ 2NH } _{ 3 }+2{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { \left( { NH } _{ 4 } \right) } _{ 2 }{ SO } _{ 4 }$


Correct Option: B
Explanation:

${ 2NH } _{ 3 }+{ H } _{ 2 }{ SO } _{ 4 }\rightarrow { \left( { NH } _{ 4 } \right)  } _{ 2 }{ SO } _{ 4 }$