Tag: nitrogen and sulfur

Questions Related to nitrogen and sulfur

When $Na$ reacts with liquid $NH _3$ the following substance is formed: 

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $[Na(NH _3) _x]^- $

  2. $ [e(NH _3 ) _y]^-$

  3. $NaNH _2$

  4. $Na _xNH _{3y}$

Show answer
Correct Option: B
Explanation:

Sodium (Na) dissolves in liquid ammonia ($NH _3$) solution to form a blue colored solution characteristic of a solvated electron in liquid ammonia which is conducting in nature due to presence of solvated electrons.

Reaction is  $ Na + (x+y)NH _3\rightarrow Na(NH _3) _x + (e(NH _3) _y)^-$
So B is correct answer. 

Ammonia and the ammonium ion can be differenciated by:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. an neutron

  2. a proton

  3. a electron

  4. hydroxide

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Correct Option: B
Explanation:

Ammonia and the ammonium ion can be differentiated by a proton $\displaystyle (H^+)$.
Ammonia is $\displaystyle NH _3$ and ammonium ion is $\displaystyle NH _4^+$.
$\displaystyle NH _3 + H^+ \rightarrow NH _4^+$

$\displaystyle Al{ Cl } _{ 3 }\left( aq \right) +{ NH } _{ 3 }\left( aq \right) + { H } _{ 2 }O\rightarrow $
Which of the following is one of the products obtained from the reaction above?

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $\displaystyle AlN$

  2. $\displaystyle Al{ H } _{ 3 }$

  3. $\displaystyle Al$

  4. $\displaystyle { Al\left( { NO } _{ 3 } \right) } _{ 3 }$

  5. $\displaystyle { Al\left( OH \right) } _{ 3 }$

Show answer
Correct Option: E
Explanation:

${ AlCl } _{ 3 }+3{ NH } _{ 3 }+3{ H } _{ 2 }O\rightarrow Al\left( OH \right) _{ 3 }+3{ NH } _{ 4 }Cl$

When heated $NH _3$ is passed over $CuO$, evolved gas is :

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $N _2$

  2. $N _2O$

  3. $HNO _3$

  4. $NO _2$

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Correct Option: A
Explanation:

When  ammonia is heated and passed over solid copper(II)oxide at high temperatures, nitrogen gas is formed.

$2NH _3(g)+3CuO(s)\rightarrow N _2(g)+3Cu(s)+3H _2O(g)$

Hence option A is correct.

When excess of ammonia is used:


 $3Cl _2+8NH _3$$\longrightarrow$$A+B$

When excess of chlorine is used:

$3Cl _2+4NH _3$$\longrightarrow$$C+D$

The oxidation state of nitrogen in compound $D$ is:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $0$

  2. $+3$

  3. $-3$

  4. $+1$

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Correct Option: B

An alkaline earth metal $(M)$ dissolves in liquid ammonia forming a deep blue-black solution. The reaction involved is:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $M + 2NH _{3} \rightarrow M(NH _{2}) _{2} + H _{2}$

  2. $M + xNH _{3} \rightarrow [M(NH _{3}) _{x}]$

  3. $M + 2NH _{4}OH \rightarrow M(OH) _{2} + 2NH _{3}$

  4. $M + (x + 2y) NH _{3}\rightarrow [M(NH _{3}) _{x}]^{2+} + 2[e(NH _{3}) _{y}]^{-}$. (e represents electron)

Show answer
Correct Option: D
Explanation:

An alkaline earth metal $(M)$ dissolves in liquid ammonia forming a deep blue-black solution. The reaction involved is $M + (x + 2y) NH _{3}\rightarrow [M(NH _{3}) _{x}]^{2+} + 2[e(NH _{3}) _{y}]^{-}$ (e represents electron).
An alkaline earth metal $(M)$ will lose two electrons to form $M^{2+}$ ions.
$M \rightarrow M^{2+}+2e^-$
Both $M^{2+}$ ions and electrons are solvated (surrounded by ammonia molecules to form $[M(NH _{3}) _{x}]^{2+} + 2[e(NH _{3}) _{y}]^{-}$).

When ammonium nitrate is mixed with aluminium powder, we get 'ammonal', which is:

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. an explosive

  2. a solvent

  3. a paint

  4. a dye

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Correct Option: A
Explanation:
Ammonal is an explosive made up of ammonium nitrate and aluminium powder, in which the ammonium nitrate functions as an oxidizer and the aluminium as fuel.

The organic compound which was first prepared in the laboratory ?

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. Acetic acid

  2. Methane

  3. Urea

  4. All of these

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Correct Option: C
Explanation:

Urea was first discovered in urine in 1727 by the Dutch scientist Herman Boerhaave, This was the first time an organic compound was artificially synthesized from inorganic starting materials, without the involvement of living organisms.

$NH _{3} + HCI  \rightarrow $

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $NH _{4}CI$

  2. $NH _{3}CI + H$

  3. Both (a) and (b) above

  4. None of these

Show answer
Correct Option: A
Explanation:
$NH _{3} + HCI  \rightarrow NH _4Cl$
Ammonia reacts with $HCl$ to form ammonium chloride($NH _4Cl$).

Select the correct options about the solubility of the following species in $ H _2O$ and $ NH _3 $(aq).
$AgF, AgCN, AgCl, Agl, CaF _2, CaCl _2 $ :

chemistry nitrogen and sulfur ammonia-properties and uses ammonia compounds of nitrogen - ammonia

  1. $AgF$ and $CaCl _2 $ are soluble in $H _2O$

  2. $AgCN$ and $AgCl$ are soluble in $NH _3$

  3. $AgI$ and $CaF _2$ are soluble in $ H _2O $ and $ NH _3 $ (aq) both

  4. None of these

Show answer
Correct Option: A,B
Explanation:

A. $AgF$ and $CaCl _2$ are polar compounds. Hence, they are soluble in water which is a polar solvent. Thus, the option A is correct.

B. $AgCN$ and $AgCl$ form complexes with ammonia as ammonia is a very good ligand. Hence, $AgCN$ and $AgCl$ are soluble in ammonia. Thus, the option B is correct.

C. $CaF _2$ and $AgI$ are insoluble in water. Thus, the option C is incorrect.