Tag: explaining wave phenomena
Questions Related to explaining wave phenomena
Monochromatic green light of wavelength $5x{ 10 }^{ -7 }$ m illuminates a pair of slits 1 mm apart. The separation of bright lines on the interference pattern formed on a screen 2m away is
Each of the four pairs of light waves arrives at a certain point on a screen. The waves have the same wavelength. At the arrival point, their amplitudes and phase differences are :
$2 \mathrm { a } _ { 0 } , 6 \mathrm { a } _ { 0 } $ and $\pi$ rad
$3 \mathrm { a } _ { 0 } , 5 \mathrm { a } _ { 0 } $ and $\pi$ rad
$9 \mathrm { a } _ { 0 } , 7 \mathrm { a } _ { 0 } $ and $3\pi$ rad
$2 \mathrm { a } _ { 0 } , 2\mathrm { a } _ { 0 } $ and $0$
The pair/s which has greatest intensity is /are :
In Young's double slit. experiment, distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 k Then angular position of first dark fringe is
The waves of $600 \mu m$ wave length are incident normally on a slit of $1.2\ mm$ width. The value of diffraction angle corresponding to the first minima will be (in radian):
In the case of interference, The maximum and minimum intensities are in the ratio $16:9$. Then
In young's double slits experiments , the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be
Using monochromatic light of wavelength $\lambda $ an experimentalist sets up the Young's double sit experiment in three ways as shown, If the observes they $y=\beta $ the wavelenght of light used is
In young's double slit experiment, when two light waves form third minimum intensity, they have
For constructive interference to take place between two monochromatic light waves of wavelength $ \lambda $ , the path difference should be
A young double slit experiment uses a monochromatic source The shape of the interference fringes formed on a screen is