Tag: multiplication and division of integers

Questions Related to multiplication and division of integers

The product of two factors with unlike signs is ...........

  1. positive

  2. negative

  3. cannot be determined

  4. none of these


Correct Option: B
Explanation:

Let 2 and -3 be the two factors.
Clearly, $2\times-3=-6$, which is negative.
Hence, Option B is correct.

The value of $\displaystyle \frac{1\div\frac{2}{3}\times \frac{3}{4} }{1\div \frac{2}{3}\times \frac{3}{4}}$ on simplification is

  1. $\displaystyle \frac{3}{16}$

  2. $\displaystyle \frac{9}{16}$

  3. $\displaystyle \frac{1}{16}$

  4. $\displaystyle \frac{7}{16}$


Correct Option: B
Explanation:

$\frac{1\div \frac{2}{3}\times \frac{3}{4}}{1+\div \frac{2}{3}of\frac{4}{3}}$

$\frac{1\div \frac{2}{3}\times \frac{3}{4}}{1\div \frac{2}{3}\times \frac{4}{3}}$
$\frac{1\times \frac{1}{2}}{1\times \frac{8}{9}}$
$\Rightarrow \frac{1\times 2}{1\times \frac{8}{9}}$
$\Rightarrow \frac{\frac{1}{2}}{\frac{8}{9}} =\frac{9}{16}$

The value of $\displaystyle \frac{0.9\times 0.9\times 0.9+0.1\times 0.1\times 0.1}{0.9\times 0.9-0.9\times 0.1+0.1\times 0.1}$ on simplification is

  1. 0

  2. -1

  3. 2

  4. 1


Correct Option: D
Explanation:
$\frac{0.9\times 0.9\times 0.9+0.1\times 0.1\times 0.1}{0.9\times 0.9-0.9\times 0.1+0.1\times 0.1}$
=$\frac{(0.9)^{3}+(0.1)^{3}}{(0.9)^{2}-0.9\times 0.1+(0.1)^{2}}$
We know that$ a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})$
Then $\frac{(0.9+0.1)\left [ (0.9)^{2}-0.9\times 0.1+(0.1)^{2} \right ]}{(0.9)^{2}-0.9\times 0.1+(0.1)^{2}}=(0.9+0.1)=1$

The simplified value of $\displaystyle y^{4}\div y$ of $\displaystyle y^{3}\div y^{2}\times y^{5}\div y^{3}$ is

  1. 2

  2. 0

  3. -1

  4. 1


Correct Option: D
Explanation:
$y^{4}\div y ofy^{3}\div y^{2}\times y^{5}\div y^{3}$
=$y^{4}\div y\times y^{3}\div y^{2}\times y^{2}$
=$\frac{y^{4}}{y^{4}}\times \frac{y^{4}}{y^{4}}=1\times 1=1$

The product of any number and "0" is ___

  1. $1$

  2. $0$

  3. number itself

  4. none of these


Correct Option: B
Explanation:
The product of any number and zero is zero. 
Theorem: $0×a=0$ for any integer $a.$

So option B is the correct answer.

$\displaystyle (-8)\times (-2)\times (+3)\times (-4) = $ 

  1. $+192$

  2. $-192$

  3. $+28$

  4. $-4$


Correct Option: B
Explanation:

$\displaystyle (-8)\times (-2)\times (+3)\times (-4)
= +16\times  -12
= -192 $

Sixth power of (-2) is

  1. $-64$

  2. $+32$

  3. $+64$

  4. $-16$


Correct Option: C
Explanation:

$\displaystyle ({ -2 })^{ 6 }=\quad -2\times -2\times -2\times -2\times -2\times -2
= +64 $

$Factor \times Factor$ is equal to  ____ .

  1. difference

  2. multiple

  3. sum

  4. None of these


Correct Option: B
Explanation:

$×$ sign between any $2$ numbers results in the product of those numbers or the multiple. 


So, option B is the correct answer.

Value of $\displaystyle { 2 }^{ 2 }{ \times (-3) }^{ 2 }{ \times 2 }^{ 2 }{ \times (-4) }^{ 2 } $ is

  1. $2034$

  2. $2403$

  3. $2304$

  4. None of these


Correct Option: C
Explanation:

$\displaystyle { 2 }^{ 2 }{ \times (-3) }^{ 2 }{ \times 2 }^{ 2 }{ \times (-4) }^{ 2 }\ =4\times +9\times 4\times 16\ =2304$ 

$8 - [ 12 - ({ - 2 \times - 4 (4 of -4 ) }) ] $=

  1. $-132$

  2. $132$

  3. $0$

  4. None of these


Correct Option: A
Explanation:

$8 - [ 12 - ({ - 2 \times  - 4 (4 of -4 )) } ] $
$= 8 - [12 - ({ - 2 \times -4 \times  -16})]$
$= 8 - [12 - ({ - 128 })]$
$= 8 - [12 +128]$
$=8 -140$
$= -132$