Tag: physics

Questions Related to physics

Optical fibres transmit light along its axis, by the process of :

  1. total internal reflection

  2. refraction

  3. interference

  4. diffraction


Correct Option: A
Explanation:

The side-wall of optical fibre provides total internal reflection of beam of light incident on it.

In an optical fibre during transmission of light

  1. Energy increases.

  2. Energy decreases.

  3. No loss of propagation of energy takes place.

  4. Light partially reflects and refracts.


Correct Option: C
Explanation:

Attenuation is a gradual loss int he intensity of any kind of flux through a medium .in telecommunication the attenuation affect the propagation of waves and signals. so during transmission of light through  an optical fiber optical and electrical attenuators cause the loss in transmission.

Which principle is the basis for the transmission of light through fiber optic cables even if the cable is bent?

  1. Photoelectric effect

  2. Uncertainty principle

  3. Light diffraction

  4. Light polarization

  5. Total internal reflection


Correct Option: E
Explanation:

Optical fibres are used to transmit light from one place to another along curved path so it does not matter even if the cable is bent.Optical fibre transmission is based on phenomenon of total internal reflection .We must remember that optical fibre does not bend light, instead light follows a zig-zag path.

A cutted diamond sparkles because of its:

  1. high refractive index

  2. hardness

  3. emission of light by the diamond

  4. absorption of light by the diamond


Correct Option: A
Explanation:

A cutted diamond sparkles because of its high refractive index. Because of high refractive index, the light suffers total internal reflections many times. that is why it sparkles.

The velocity of light in the core of a step index fibre is $2\times { 10 }^{ 8 }m/s$ and the critical angle at the core-cladding interfere is ${ 80 }^{ 0 }$. Find the numerical aperture and the acceptance angle for the fibre in air. The velocity of light in vacuum is $3\times { 10 }^{ 8 }m/s$.

  1. 0.264; $75.{ 3 }^{ 0 }$
  2. 0.464; $45.{ 3 }^{ 0 }$
  3. 0.364; $25.{ 3 }^{ 0 }$
  4. 0.264; $15.{ 3 }^{ 0 }$

Correct Option: D

The optical path of a monochromatic light is the same if it goes through $2.00$ cm of glass or x cm of ruby. If the refractive index of glass is $1.510$ and that of ruby is $1.760$ find the value of x is _______ cm?

  1. $1.716$

  2. $1.525$

  3. $2.716$

  4. $2.525$


Correct Option: A
Explanation:

We know optical path =Refractive index $\mu \times$ length $x$=constant

Therefore ${ \mu  } _{ glass }{ x } _{ glass }={ \mu  } _{ ruby }{ x } _{ ruby }\ { x } _{ ruby }=\dfrac { { \mu  } _{ glass }{ x } _{ glass } }{ { \mu  } _{ ruby } } =\frac { 1.51\times 2 }{ 1.76 } =1.716$

Consider telecommunication through optical fibres. Which of the following statements is NOT true? 

  1. Optical fobres can be of graded refractive index

  2. Optical fibres are subjected to electromagnetic interference from outside

  3. Optical fibres have extremely low transmission loss

  4. Optical fibres may have homogeneous core with a suitable cladding


Correct Option: B

Optical fibre, which is used in communication, works on which principle?

  1. Dispersion

  2. Total Internal reflection

  3. Reflection

  4. Refraction


Correct Option: B

Optical fiber communication is based on which of the following phenomena:- 

  1. Total internal reflection

  2. Scattering

  3. Reflection

  4. Interference


Correct Option: A

If parabolic profile is used for refractive index in the core, what is the name given to such core?

  1. single mode core

  2. multi mode core

  3. differential mode core

  4. curvilinear differential core


Correct Option: D
Explanation:

Optical fibers work on the phenomenon of total internal reflection inside the fiber tube. Thin fiber tubes carry optical images to large distances,around 100 km.

The losses in the fiber is due to Raman scattering, polarization and diffraction. The loss due to diffraction can be minimized by using differential cores, that is, by having varying refractive index along the radial direction.
When these cores are parabolic, the loss is least. Such cores are called curvilinear differential cores.