Tag: maths

$(-144)\div (+16)=\dfrac { -144 }{ 16 } \ =-(\dfrac { 144 }{ 16 } )\ =-(9)$

Given, $

\dfrac { (-16)\times (-8) \times (-81) }{ (-18)\times 32 } $

As there are $ 3 $ negative numbers in the numerator and $ 1 $ in the denominator, the answer will be positive. 

 
Canceling out the common factors and simplifying we get

$ \dfrac { (-16)\times (-8) \times (-81) }{ (-18)\times 32 }=\dfrac{4 \times 81}{9 \times2}   = 18 $

$96\times (-25) \div (-75)\times (-16)$
$=-2400\div 1200$
$=-2$

Since $231$ is an odd number, the product of $231$ negative integers will be negative.

The positive integer whose product with $-1$ is negative.

Let us take two integers, one with positive sign and one with negative sign that is $+2$ and $-5$ then the product of these integers with different/unlike signs is:

Let us take two integers with positive signs that is $+2$ and $+5$ then the product of these integers with same/like signs is:

$-112 \times (-1) = +112$

$(132)\div (-12)=\frac{132}{-12}$
                             $=\frac{12\times11}{-12}$
                             $=-1\times11$
                             $=-11$
Option D is correct.

(-1) $\times$ (-1) $\times$ (-I)......evensign = Positive